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klemol [59]
3 years ago
10

The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu

Chemistry
2 answers:
Eddi Din [679]3 years ago
8 0

Answer:

0.002389

Explanation:

Use the equation the other person used to answer but with the numbers that are given on this assignment!

Inessa [10]3 years ago
5 0

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

^{A}_{Z}X \rightarrow ^{2}_{1}H  

The mass defect can be calculated by using the following equation:

\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}

Where:

Z: is the number of protons = 1

A: is the mass number = 2      

m_{p}: is the proton's mass = 1.00728 amu  

m_{n}: is the neutron's mass = 1.00867 amu

m_{a}: is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!  

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