Answer:
Oh, you need to get the blue dots, and move them to the table or graph to plot them!
Hope that makes sense!
Answer: Tyndall effect is the scattering of light due dispersed colloidal particles that does not settle in a solution. Colloidal particles constantly moves because of Brownian motion and blocks or hinders light particles to pass through. Colloidal particles are medium sized particles but smaller enough than suspension.
Explanation:
Answer:
45 °C.
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 1125 J
Mass (M) = 250 g
Final temperature (T₂) = 55 °C
Specific heat capacity (C) = 0.45 J/gºC
Initial temperature (T₁) =?
The initial temperature of the iron can be obtained as illustrated below:
Q = MC(T₂ – T₁)
1125 = 250 × 0.45 (55 – T₁)
1125 = 112.5 (55 – T₁)
Divide both side by 112.5
1125/112.5 = 55 – T₁
10 = 55 – T₁
Collect like terms
10 – 55 = –T₁
–45 = –T₁
Multiply through by –1
45 = T₁
T₁ = 45 °C
Therefore, the initial temperature of the iron is 45 °C
Answer:
Explanation:
To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.
Step 1: write out the equation and balance it.
Al+ 3mno2=3mn+ 2Alo3.
The limiting reactant is mn02 because it is not found in excess.
Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8
All=67.2÷100×290(total gram of the reactants)=194.88g
Mno2=32.8÷100×290g=94.12g.
Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.
Mno2=54.938+ (16)2=86.98g/mol.
Mn=54.938.
Step 4:
From your balanced equation , calculate mn.
94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.
94.12g×1÷86.98g×3÷4×54.938÷1
=44.58g
An element is <span>a part or aspect of something abstract, especially one that is essential or characteristic. I hope this helps you good luck :)</span>
