Answer:
D
Explanation:
The gravitational force between any two objects is affected by the masses of the objects and the distance between them. The greater the masses of the objects are, the stronger the gravitational force is.
Since all four of the satellites are the same distance from the Earth's surface, only their masses affect the strength of the gravitational force. At 903 kilograms, satellite D has the greatest mass, so the gravitational force pulling it toward the Earth is the greatest.
Answer:
vavg = 53.7 km/h
Explanation:
In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:
where xf - xo = total displacement = 1250 Km
If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h
⇒ 
Answer:
this is answer please mark me as brainlest
Explanation:
A force of 500N acts on the area of 2.5m2; calculate the pressure
exerted,
(Ans: 200 Pa]
b. Calculate the force applied when 400 Pa of pressure is exerted by a box
of surface area 2m2.
(Ans: 800 N]
The weight of a stone is 1400N. If it exerts a pressure of 700 Pa, calculate
the area.
(Ans: 2m]
d. A force of 2000 N acts on 5m² surface area. Calculate the pressure
exerted.
(Ans: 400 Pa]
c.
Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
