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dalvyx [7]
3 years ago
11

A bus leaves New York City, takes a non-direct route and arrives in St. Louis, Missouri 23 hours, 16 minutes later. If the dista

nce between the two cities is 1250 km, what is the magnitude of the bus' average velocity?
Physics
1 answer:
german3 years ago
8 0

Answer:

vavg = 53.7 km/h

Explanation:

In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:

vavg =\frac{xf-xo}{t-to}

where xf - xo = total displacement = 1250 Km

If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h

⇒ vavg =\frac{1250 km}{23.27h}  =  53.7 Km/h

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The speed limit sign in indiana reads 60 miles per hour. convert these units to meters per second
cluponka [151]

Answer:

26.822 m/s

Explanation:

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3 0
2 years ago
A 0.5 kg block slides down a frictionless semicircular track from a height, h, and collides with a second 1.5 kg block at the bo
Ede4ka [16]

Answer:

h' = 0.062\cdot h

Explanation:

The speed of the 0.5 kg block just before the collision is found by the Principle of Energy Conservation:

U_{g} = K

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot h}

v \approx 4.429\cdot \sqrt{h}

Knowing that collision is inelastic, the speed just after the collision is determined with the help of the Principle of Momentum Conservation:

(0.5\,kg) \cdot (4.429\cdot \sqrt{h}) = (2\,kg)\cdot v

v = 1.107\cdot \sqrt{h}

Lastly, the height reached by the two blocks is:

K = U_{g}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot h'

h' = \frac{v^{2}}{2\cdot g}

h' = \frac{(1.107\cdot \sqrt{h})^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

h' = 0.062\cdot h

3 0
3 years ago
What is the strength of the electric field of a point charge of magnitude +4.8 × 10^-19 C at a distance of 4.0 × 10^-3 m? A. 3.6
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Answer is D -  from the equation of electric field for point charge
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If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?
disa [49]

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
  • From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
  • As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
  • Steel is a magnetic material.
  • Magnetic materials gets attracted  to the magnet at both the North and South pole.
  • This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

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