Which of the following statements is NOT true?

Mathematics

1 answer:

Ludmilka [50]3 years ago

8 0

Answer

it think it is 2 and 4 if i am wrong i will edit my work

Step-by-step explanation:

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Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago

I asked this earlier and got no answer. Will give brainliest

Virty [35]

The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

A(s) = s^2

Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

s = sqrt(225)

s = 15

So, the dimensions are 15 x 15 in

6 0

3 years ago

The 100th term in 8, 13, 18,23, 28,...

Lunna [17]

Answer:

The 100th term of the sequence is 503.

Step-by-step explanation:

Given : Sequence 8, 13, 18,23, 28,...

To find : The 100th term in the sequence ?

Solution :

Sequence 8, 13, 18,23, 28,... is the arithmetic sequence

Where, First term is a=8