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k0ka [10]
3 years ago
11

In which of the following is the solution concentration expressed in terms of molarity?

Chemistry
2 answers:
puteri [66]3 years ago
8 0
Answer:
D. <span>10 mol of solute/ 1L of solution

Explanation:
Molarity is used to express the concentration of the solution. It is expressed as the number of moles of solute per liter of solution

Molarity = moles of solute / liters of solution
This means that molarity has the units moles/liter

The only option satisfying this is the last one.

Hope this helps :)</span>
kifflom [539]3 years ago
6 0

The solution concentration that is expressed in terms of molarity is as follows:

\boxed{{\text{D}}{\text{. 10 mol of solute/1 L of solution}}}.

Further Explanation:

Concentration describes relationship between different components of solution. In order to indicate concentration of different types of solutions, various concentration terms are used. Some of these are mentioned below.

1. Molarity (M)

2. Mole fraction (X)

3. Molality (m)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

7. Parts per billion (ppb)

A. 10 g of solute/1000 g of solution

Mass percent is defined as the ratio of mass of solute to that of solution. Since above expression is the ratio of mass of solute to mass of solution, it is expressed as mass percent and not molarity.

B.10 g of solute/1000 mL of solution

Density is defined as mass per unit volume. Since above expression is the ratio of mass to volume, it is expressed as density and not molarity.

C. 10 mL of solute/1 L of solution

Volume percent is defined as the volume of solute divided by the total volume of solution. Since above expression is the ratio of volume of solute to volume of solution, it is expressed as volume percent and not molarity.

D. 10 mol of solute/1 L of solution

Molarity is defined as moles of solute that can be dissolved in one liter of solution. Since above expression is the ratio of amount of solute to the volume of solution in liters, it is expressed as molarity of solution.

Hence, option D represents the solution in terms of molarity.

Learn more:

  1. Calculation of volume of gas: brainly.com/question/3636135
  2. Determine how many moles of water produce: brainly.com/question/1405182

Answer details:

Grade:Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: molarity, volume of solution, amount of solute, mass percent, volume percent, density, concentration terms.

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sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

T_2 = -2.0 + 273.15 = 271.15 K

P_1 = 1.02 atm

T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

1.02atm(271.15K)=P_2(293.45K)

P_2=\frac{1.02atm*271.15K}{293.45K}

P_2 = 0.942 atm

So, the new pressure of the jar is 0.942 atm.


5 0
4 years ago
In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc
natita [175]

Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water 

x= 0.7535 g water




3 0
3 years ago
What should a simplified model of a large molecule like glucose show?
maxonik [38]

Glucose is the simplest sugar and carbohydrate that provides energy. The simplified model of glucose (C₆H₁₂O₆) shows carbon, hydrogen, and oxygen atoms linked together.

<h3>What is glucose?</h3>

Glucose is an example of a carbohydrate macromolecule that is further classified as a monosaccharide. They are crystalline and fundamental units of carbohydrates.

The molecular formula of glucose is C₆H₁₂O₆ and the mass is 180.156 g/mol. It is an aldohexose that contains an aldehydic functional group. In its structure, there are six oxygen atoms, six carbon atoms, and twelve hydrogen atoms.

Therefore, the glucose molecule is composed of C, H, and O.

Learn more about glucose here:

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5 0
1 year ago
A chemist adds 485 mL of a 0.0025 mol/L calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sul
viva [34]

Answer : The mass in grams of calcium sulfate is 0.16 grams.

Explanation :

Molarity : It is defined as the number of moles of solute present in one litre of solution.

Formula used :

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution}}

Solute is, CaSO_4

Given:

Molarity of CaSO_4 = 0.0025 mol/L

Molar mass of CaSO_4 = 136 g/mole

Volume of solution = 485 mL

Now put all the given values in the above formula, we get:

0.0025=\frac{\text{Mass of }CaSO_4\times 1000}{136\times 485}

\text{Mass of }CaSO_4=0.16g

Thus, the mass in grams of calcium sulfate is 0.16 grams.

6 0
3 years ago
1)
Delicious77 [7]

Answer:

<u><em></em></u>

  • <u><em>C) How much energy was added to the substance to increase molecule motion? </em></u>

Explanation:

<em>The most relevant question to ask regarding this change</em> must take into account the physical knowledge about matter.

When matter changes from<em> liquid </em>state to <em>gaseous</em> state, a physical change called evaporation, the particles (molecules or atoms) of the <em>pure substance </em>will separate from each other, take up more space and move faster.

<em>Condensation</em> is the opposite to evaporation, thus the option A) is not the most relevant question.

<em>The charge of the particles</em> does not change; so the option B) is not relevant at all.

The particles should gain energy from the surroundings to <em>increase</em> their <em>motion</em> (kinetic energy) when they pass from liquid state, where they move slower, to gas state, where they move faster. Hence, the option<em> C), How much energy was added to the substance to increase molecule motion?</em> , is totally relevant.

Since this is an increase in the <em>kinetic energy of the molecules</em>, the option D) is not relevant.

6 0
3 years ago
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