A light-year is the distance light travels in one year. 6 trillion miles
Correct me if I’m wrong
Answer:
Explanation:
The hybridization of the any molecule can be calculated by the formula 
We know that Xe have 8 valence electron and 2 monovalent atom (F) are attached with Xe and there is no charge
So hybridization 
So the hybridization will be
Note -
2 for sp
3 for 
4 for 
5 for
Answer:
An element's atomic number is equal to the number of protons in the nuclei of any of its atoms. The mass number of an atom is the sum of the protons and neutrons in the atom. Isotopes are atoms of the same element (same number of protons) that have different numbers of neutrons in their atomic nuclei
The change in heat is simply equal to:
change in heat ΔH = final enthalpy – initial enthalpy
ΔH = [280.25 g * 4.18J/gC * (17.5°C)] – [280 g * 4.18J/gC
* 13.5°C]
ΔH = 4,699.89 J = 4.7 kJ
<span>Hence heat released is about 4.7 kJ</span>
Answer:
First, let's determine how many moles of oxygen we have.
Atomic weight oxygen = 15.999
Molar mass O2 = 2*15.999 = 31.998 g/mol
We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml
Since the density is 1.149 g/mol,
we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2
Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol
Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)
Now take the formula and solve for V, then substitute the known values and solve.
PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L
So the volume (rounded to 3 significant figures) will be 134 ml.
