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3 years ago

Hello it's my new id myself numu

Chemistry

2 answers:

zavuch27 [327]3 years ago

7 0

Answer:

Hi numu !

How are you .

Hope you have nice time

zaharov [31]3 years ago

3 0

Answer:

Hi numu I'm Tanvi

Explanation:

how r u?

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An exothermic reaction occurs spontaneously ,why?

Delvig [45]

Answer:

See below

Step-by-step explanation:

An exothermic reaction tends to occur spontaneously because the products are more stable than the reactants.

Nature tries to get to the lowest energy state.

4 0

3 years ago

Which of the following affects how strongly anions and cations are attra

kozerog [31]

Answer:

C. Neutrons .

Explanation:

You already have a cation ad an anion (a + and a - charge) and distance I think is how strong that attraction is. It varies as 1/r^2.

8 0

3 years ago

Read 2 more answers

A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t

gulaghasi [49]

Answer:

$\large \boxed{\text{45.1 g/mol}}$

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Data:

t₂ = 222 s

t₁ = 175 s

M₁ = 28.01

Calculation :

$\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}$