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dalvyx [7]
2 years ago
7

How many moles are in 1.2 x 103 grams of ammonia, NH3?

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
6 0
I believe the answer is 70.6 moles
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An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

Volume= 236 mL x (\frac{1 L}{1000 mL}) = .236 L

Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

MM= 49.2 g/mol

3 0
2 years ago
In most lewis dot structures of neutral compounds, carbon as the central atom will be bound to a maximum of how many atoms, nitr
Fittoniya [83]
The total number of elements that one particular element can bond to can be determined by simply drawing the Lewis structure of the element.

Place the chemical symbol
Then look at the group number = valence electrons
Distribute the valence electrons around the atom.

C = 4 bonds
N = 3 bonds
O = 2 bonds
7 0
3 years ago
Balance the following oxidation-reduction reactions, which take place in acidic solution, by using the "half-reaction" method.
LuckyWell [14K]
First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced. 

Mg --> Mg+2 
 
<span>Hg+2 --> Hg+1 
</span>
Then you have to balance each half reaction first with electrons before adding them together in one equation

Mg ⇒ Mg^{+2}  +  2e^{-1}

and

2Hg^{+2} + 2e^{-1} ⇒ Hg_{2} ^{+2}
 
and then combine them together to form 

Mg + 2 Hg^{+2} + 2e ⇒ Mg^{+2} + 2e ^{-} + 2 Hg^{+1} + 2 e^{-}

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: A<span>dd H+ and H2O to balance the H's and O's in acidic solution if needed.</span>
8 0
3 years ago
Are specimens the best source of DNA
xxTIMURxx [149]

no the best source is blood.

5 0
3 years ago
Significant Digits and Scientific Notation Part 1: Determine the number of significant digits in each number and write out the s
MA_775_DIABLO [31]

Answer:

1. 6 significant digits. 2. 2 significant digits. 3. 8 significant digits. 4. 4 significant digits. 5. 8 significant digits. 6. 7 significant digits. 7. 2 significant digits.

Explanation:

All nonzero digits are significant. All zeros before nonzeros are insignificant. All zeros after nonzeros are insignificant unless they are made for precision of some data. So 405000 may have 3 or 6 significant figures. But usually all zero figures after significant digits are significant.

8 0
3 years ago
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