Answer:
Blue
Explanation:
depending on how you use the color you can affect of the mood of the painting if there are dark blue clouds it seems dark but if you use light blue for the sky it can seem happy
Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.
Explanation:
Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.
A+ have Agglutination with Anti-A ,Anti-Rh and No agglutination with Anti-B.
A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.
B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.
B- have Agglutination with Anti-B and No agglutination with Anti-B and Anti-Rh.
Rh+ have Agglutination with Anti-A and Anti-Rh and No agglutination with Anti-B.
Rh- have No Agglutination with Anti-A and Anti-B and Anti-Rh.
Answer : The total pressure in the flask is 1.86 atm.
Explanation :
First we have to calculate the pressure of
gas.
Using ideal gas equation :

where,
P = Pressure of
gas = ?
V = Volume of
gas = 765 mL = 0.765 L (1 L = 1000 mL)
n = number of moles
w = mass of
gas = 1.25 g
M = molar mass of
gas = 44 g/mol
R = Gas constant = 
T = Temperature of
gas = 
Putting values in above equation, we get:


Now we have to calculate the total pressure in the flask.

Given :


conversion used : (1 atm = 760 mmHg)
Now put all the given values in the above expression, we get:

Therefore, the total pressure in the flask is 1.86 atm.
Answer: B or C
Explanation: The question does not include the variable or steps Brian is using so either one could be correct. It has to be the one that he is controlling though. This is because a control group is used to rule out any alternate explanations. Therefore the answer should be the one that he is trying to test out.
Answer:
ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)
Explanation:
First, we will write the molecular equation, since it is easier to balance.
2 HBr(aq) + ZnS(s) ⇄ H₂S(aq) + ZnBr₂(aq)
In the full ionic equation we include all ions and molecular species.
2 H⁺(aq) + 2 Br⁻(aq) + ZnS(s) ⇄ 2 H⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + 2 Br⁻(aq)
In the net ionic equation we include only the ions that participate in the reaction and the molecular species.
ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)