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Dimas [21]
3 years ago
9

The dissolution of barium hydroxide in water is an exothermic process. Which of the following statements is correct?A) The entha

lpy of solid barium hydroxide plus pure water is less than that of the solution, at the same temperature.B) The enthalpy of solid barium hydroxide plus pure water is greater than that of the solution, at the same temperature.C) The enthalpy of solid barium hydroxide plus pure water is the same as that of the solution, at the same temperature.D) The temperature of the solution is lower than of the barium hydroxide and water before mixing.E) When barium hydroxide dissolves in water, the system does work on the surroundings.
Chemistry
2 answers:
madreJ [45]3 years ago
8 0

Answer:

B

Explanation:

An exothermic reaction is one in which heat is liberated to the surrounding by a reaction.In this case,the enthalpy of the product is less than that of the reactant and such  a reaction has a negative enthalpy (ΔH).

Marta_Voda [28]3 years ago
5 0

Answer:

B

Explanation:

In an exothermic process the enthalpy of the products is smaller than the enthalpy of the reactives, in other words, the difference of enthalpy of the process (which is defined as the enthalpy at the final state of the process minus the enthalpy of the initial state) is negative. In this case, this means that the enthalpy of solid barium hydroxide plus pure water is greater than that of the solution, at the same temperature .

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Calculate ΔH when 2 moles of ethanol (C2H5OH) reacts with excess oxygen according to the following thermochemical equation?C2H5O
klio [65]

Answer:

–2733.4 KJ

Explanation:

The balanced equation for the reaction is given below:

C₂H₅OH + 3O₂ —> 2CO₂ + 3H₂O

ΔH = −1366.7 kJ

From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:

From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.

Thus, enthalpy change (ΔH) obtained is –2733.4 KJ

5 0
3 years ago
Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19​
beks73 [17]

Answer:

E = 3.6×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 550 nm  (550 ×10⁻⁹ nm)

Energy of wave = ?

Solution:

Formula:

E = h c/λ

c = 3×10⁸ m/s

h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm

E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm

E = 0.036×10⁻¹⁷ J

E = 3.6×10⁻¹⁹ J

3 0
2 years ago
Calcium chloride contains only calcium and chloride. What is the formula for this compound?
nataly862011 [7]
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4 0
3 years ago
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Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag Express your answer as a b
Alinara [238K]

Answer:

Explanation:

The cell reaction properly written is shown below:

              Cu|Cu²⁺_{aq} || Ag⁺_{aq} | Ag

From this cell reaction, to get the net ionic equation, we have to split the reaction into their proper oxidation and reduction halves. This way, we can know that is happening at the electrodes and derive the overall net equation.

  Oxidation half:

                  Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

At the anode, oxidation occurs.

  Reduction half:

                  Ag⁺_{aq} + 2e⁻ ⇄ Ag_{s}

At the cathode, reduction occurs.

To derive the overall reaction, we must balance the atoms and charges:

             Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

              Ag⁺_{aq} + e⁻ ⇄ Ag_{s}

  we multiply the second reaction by 2 to balance up:

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The net reaction equation:

Cu_{s} + 2Ag⁺_{aq} + 2e⁻⇄ Cu²⁺_{aq} + 2e⁻ + 2Ag_{s}

We then cancel out the electrons from both sides since they appear on both the reactant and product side:

  Cu_{s} + 2Ag⁺_{aq} ⇄ Cu²⁺_{aq} + 2Ag_{s}

6 0
2 years ago
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Pavlova-9 [17]
D is the answer. A, B,C are absurd. Doing a little word right there.
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3 years ago
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