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Helga [31]
3 years ago
12

The particles in both gases and liquids select one:

Chemistry
1 answer:
Semmy [17]3 years ago
6 0
A is the answer, it cant be B cause liquid cant change with ither particles. It cant be C cause gases dont vibrate they slide over each ither. It cant be D cause solid is the one closely packed together
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What was the result of the difference in temperatures within the early solar system as the planets formed?
miskamm [114]

Answer:the awenser is b

Explanation:

cause

6 0
2 years ago
A cubic object has a volume of 250 cm. What is its density if its mass is 5 points<br> 257.3 g?
ira [324]

Answer:

<h3>The answer is 1.03 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 257.3 g

volume = 250 cm³

We have

density =  \frac{257.3}{250}  \\  = 1.0292

We have the final answer as

<h3>1.03 g/cm³</h3>

Hope this helps you

8 0
3 years ago
Consider the reaction: 2BrF3(g) --&gt; Br2(g) + 3F2(g)
riadik2000 [5.3K]

Answer : The entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

2BrF_3(g)\rightarrow Br_2(g)+3F_2(g)

The expression used for entropy change of reaction (\Delta S^o) is:

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]

where,

\Delta S^o = entropy change of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

\Delta S_f^0_{(Br_2)} = 245.463 J/mol.K

\Delta S_f^0_{(F_2)} = 202.78 J/mol.K

\Delta S_f^0_{(BrF_3)} = 292.53 J/mol.K

Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]

\Delta S^o=268.74J/K

Now we have to calculate the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of BrF_3 has entropy change = 268.74 J/K

So, 1.62 moles of BrF_3 has entropy change = \frac{1.62}{2}\times 268.74=217.68J/K

Therefore, the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

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4 years ago
Which of the following structures surround cells?
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Q1. What are Ceres, Ida, and Gaspra?
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