Answer:
Weight of boulder = 22,400 gram
Explanation:
Given:
Volume = 8,000 cm³
Density = 2.8
Find:
Weight of boulder
Computation:
Weight of boulder = Volume x Density
Weight of boulder = 8,000 x 2.8
Weight of boulder = 22,400 gram
It is either a proton or a neutron
Answer:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:
![\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S](https://tex.z-dn.net/?f=%5CDelta%20G%3D-RTln%28Ksp%29%5C%5C%5C%5C%5CDelta%20G%3D%5CDelta%20H-T%5CDelta%20S)
Thus, by combining them, we obtain:
![-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}](https://tex.z-dn.net/?f=-RTln%28Ksp%29%3D%5CDelta%20H-T%5CDelta%20S%5C%5C%5C%5Cln%28Ksp%29%3D-%5Cfrac%7B%5CDelta%20H%7D%7BRT%7D%20%2B%5Cfrac%7BT%5CDelta%20S%7D%7BRT%7D%20%5C%5C%5C%5Cln%28Ksp%29%3D-%5Cfrac%7B%5CDelta%20H%7D%7BRT%7D%20%2B%5Cfrac%7B%5CDelta%20S%7D%7BR%7D)
Which is related to the general line equation:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Whereas:
![y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}](https://tex.z-dn.net/?f=y%3Dln%28Ksp%29%5C%5C%5C%5Cm%3D-%5Cfrac%7B%5CDelta%20H%7D%7BR%7D%20%5C%5C%5C%5Cx%3D%5Cfrac%7B1%7D%7BT%7D%20%5C%5C%5C%5Cb%3D%5Cfrac%7B%5CDelta%20S%7D%7BR%7D)
It means that we answer to the blanks as follows:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Regards!
All of them are properties of compounds except III.
for I, compounds are chemically combined together, so to separate them, we must use chemical methods like electrolysis or applying heat. These requires large amount of energy.
For II, they're always fixed. For example, in water (H2O), the ratio of hydrogen and oxygen is always 1:8 in mass. If there's some extra added, the substance becomes mixture instead of compounds.
For IV, after you chemically combined elements or compounds together, their properties are completely different. For example, iron can be attracted to magnets, but iron II sulphide does not.
Answer:
0.62 N
Explanation:
first of all: 3.0 s = 0.05 m
Let ? be the work that brakes do at 3.0s
24 m ----> 299 N
0.05 m ---->?
? = (0.05 m x 299 N)/ 24
? = (14.95)/ 24
? = 0.622 N