The half-life of Th-232 is 1.405 × 10¹⁰ years
Time elapsed = 2.8 x 10⁹ years
Equation of radioactive decay:
A = A₀ = (1/2)^ t/t₁/₂
where A₀ is the initial amount, A is the amount after time t, t₁/₂ is the half file
The fraction of thorium-232 that remains in the rock after 2.8 billions years is,
A/A₀ = (1/2) ^ (2.8 x 10⁹/ 1.405 × 10¹⁰) = 0.871
Therefore, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%
Yep! I typed your equation into this website"http://www.endmemo.com/chem/balancer.php" and it said it was balanced
Answer: I think probaly wrong so probaly dont
listen to me
Explanation:
As a trend or pattern, the atomic radius decreases as you go left to right across the period, but increases as you go down a particular group.
Answer:
c. 5days
Explanation:
there is no question but if it's a graph
the answer is 5days
