All categories

4 years ago

Al+Mn2+>Al3++Mn. How many electrons will be lost in all?

Chemistry

1 answer:

Alisiya [41]4 years ago

5 0

It is probably 6 just divide

You might be interested in

The following compound can be identified as

sergeinik [125]

Answer:

3: Lactone

Explanation:

Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.

Thus, looking at the question, it has the structure as defined in Lactones.

Thus, we can say that the compound is a Lactone.

5 0

3 years ago

Increasing the temperature of a solution will slow down the dissolving/dissolution of the solute.

expeople1 [14]

Answer:

False

Explanation:

It will actually speed it up

7 0

3 years ago

The ph of 0.010 m aqueous aniline is 8.32. What is the percentage protonated?

LekaFEV [45]

Answer : The percentage aniline protonated is, 0.0209 %

Explanation :

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-8.32\\\\pOH=5.68$

Now we have to calculate the hydroxide ion concentration.

$pOH=-\log [OH^-]$

$5.68=-\log [OH^-]$

$[OH^-]=2.09\times 10^{-6}M$

The equilibrium chemical reaction will be:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

From the reaction we conclude that,

Concentration of $OH^-$ ion = Concentration of $NH_4^+$ ion = $2.09\times 10^{-6}M$

Now we have to calculate the percentage aniline protonated.

$\text{percentage aniline protonated}=\frac{2.09\times 10^{-6}M}{0.010M}\times 100$

$\text{percentage aniline protonated}=0.0209\%$

Thus, the percentage aniline protonated is, 0.0209 %

7 0

4 years ago

Which of the following is one stage of the cell cycle?

ASHA 777 [7]

Answer: A

Explanation: cytokinesis is in the M phase.... Mitosis is followed by cytokinesis (cell separation)

4 0

3 years ago

Iron reacts with oxygen gas to produce iron (III) oxide. If there are 52 grams of

IRISSAK [1]

Mass of Fe₂O₃ : 74.26 g

Volume of O₂ at STP = 15.624 L

<h3>Further explanation</h3>

Reaction

4Fe (s) + 3O₂ (g) ==> 2Fe₂O₃ (s)

mol Fe :

Ar Fe = 56 g/mol

$\tt \dfrac{52}{56}=0.93$

mol Fe₂O₃ :

$\tt \dfrac{2}{4}\times 0.93=0.465$

mass Fe₂O₃ :

MW Fe₂O₃ : 159,69 g/mol

$\tt 0.465\times 159,69=74.26~g$

mol O₂ :

$\tt \dfrac{3}{4}\times 0.93=0.6975$

volume O₂ at STP(1 mol=22.4 L)

$\tt 0.6975\times 22.4=15.624~L$

7 0

3 years ago