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dezoksy [38]
3 years ago
5

A sensational 130 kg midfielder has 695 J of

Physics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

v = 3.27 m/s

Explanation:

KE = 1/2 mv^2

695 J = 1/2 (130kg)(v^2)

695 J / (1/2 x 130kg) = v^2

v^2 = square root of 10.69

v = 3.27 m/s

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dlinn [17]
First, we will get the resultant force:
The direction of the force due to the person's weight is vertically down.
weight of person = 700 newton

Assume that the force exerted by the arms has a vertically upwards direction.
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Then we will calculate the acceleration of the resultant force:
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V^2 = U^2 + 2aS
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Based on the above calculations:
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