displacement is given by equation

now at t = 5 s the position is

similarly position at t = 9 s

so the displacement of object in given interval of time will be

time interval

now the average velocity will be given as


so its average speed is 252 m/s
The cornea is responsible of refraction light 1/3 in eye.
<h3>What is the function of the cornea?</h3>
In addition to the protective function, it plays a fundamental role in the formation of vision. Transparent, it works like a lens over the iris, focusing light from the pupil towards the retina.
Normally, the cornea and lens deflect (refract) incoming light rays, focusing them on the retina. The shape of the cornea is fixed, but the lens changes shape to focus on objects at different distances from the eye.
See more about cornea at brainly.com/question/2297282
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Answer:
5.15348 Beats/s
4.55 mm
Explanation:
= Velocity of sound = 342 m/s
= Velocity of sound = 346 m/s
= First frequency = 440 Hz
Frequency is given by

Beat frequency is given by

Beat frequency is 5.15348 Hz
Wavelength is given by

Relation between length of the flute and wavelength is

At v = 346 m/s


Difference in length is

It extends to 4.55 mm
Gravity Gravitational Force of Gravity
Answer:
B. The same on the moon.
Explanation:
The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.

When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.
Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.
So, the correct option is:
<u>B. The same on the moon.</u>