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Ne4ueva [31]
4 years ago
9

25 POINTS and brainiest answer for General Science help!

Physics
2 answers:
Pavlova-9 [17]4 years ago
7 0
I think that the answer would be c
babymother [125]4 years ago
3 0

The answer is C. I had this question before so I know.

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A 17926-lb truck enters an emergency exit ramp at a speed of 75.6 ft/s. It travels for 6.4 s before its speed is reduced to 30.3
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Answer:

F_{braking}=337299 pdl

Explanation:

Impulse-Momentum relation:

I=\Delta p\\ F_{total}*t=m(v_{f}-v{o})

F_{total}=-F_{braking}+mgsin{\theta}

We solve the equations in order to find the braking force:

F_{braking}=m(v_{o}-v{f})/t+mgsin{\theta}=17926(75.6-30.3)/6.4+17926*32.17*sin21.4=337299 pdl

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A 5000.0-kg car goes from 0 m/s to 70 m/s in 3600 seconds. What is the accelera
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given:

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