Select the single best answer. Explain why (CH3)2CHCH(Br)CH2CH3 reacts faster than (CH3)2CHCH2CH(Br)CH3 in an E2 reaction, even
though both alkyl halides are 2°. The second structure has more hydrogens attached to the β carbons than the first structure. The first structure has more hydrogens attached to the β carbons than the second structure. The major and minor products formed from the first structure have more alkyl groups on the C═C than those formed from the second structure. The major and minor products formed from the second structure have more alkyl groups on the C═C than those formed from the first structure.
The major and minor products formed from the first structure have more alkyl groups on the C═C than those formed from the second structure
Explanation:
When we consider the structures of the major and minor products from the dehydrohalogenation of structure 1 by E2 mechanism, it is easy to see that the both products are highly substituted by alkyl groups. It is a fact in organic chemistry that the more substituted an alkene is the more stable it is and the more quickly it is formed; Hence the answer
Acetylene has a chemical formula which can be written as:
C2H2
We can see that there are two positive ions, H+. Now what
deprotonation means is that the H+ is removed from acetylene to form acetylene
ion and water. In this case, I believe that the answer would be:
