The moles of the gas in the sample is 0.391 moles
calculation
by use of ideal gas equation, that is Pv=nRT
where n is number of moles
P(pressure)= 660 mmhg
R(gas constant) = 62.364 l.mmhg/mol.K
T(temperature)= 25 +273 = 298 k
by making n the subject of the formula
n= Pv/ RT
n is therefore= (660mm hg x11 L)/( 62.364 L.mmhg/mol.k x298 K) = 0.391 moles
Explanation:
The given reaction is as follows.
![E + S \rightleftharpoons ES \xrightarrow[]{k_{2}} E + P](https://tex.z-dn.net/?f=E%20%2B%20S%20%5Crightleftharpoons%20ES%20%5Cxrightarrow%5B%5D%7Bk_%7B2%7D%7D%20E%20%2B%20P)
Here, [E] = triose phosphate isomerase = 0.1 
[S] = Dihydroxy acetone phosphate = 5 
[P] = Glyceraldehyde-3-phosphate = 2 
Therefore, velocity of the reaction will be as follows.
v = ![\frac{d[P]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BP%5D%7D%7Bdt%7D)
= ![\frac{K_{2}[E][S]}{K_{M} + [S]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_%7B2%7D%5BE%5D%5BS%5D%7D%7BK_%7BM%7D%20%2B%20%5BS%5D%7D)
where, 
= Michaelic menten constant = 
v = 
= 
or, = 30 nm/s
Hence, we can conclude that the actual velocity of the forward reaction under physiologic conditions if KM = 10 μM is 30 nm/s.
Answer:
1. 0.073L
2. 0.028L
3. 0.014L
Explanation:
The volume for the different solutions are obtained as shown below:
1. Mole = 0.53mol
Molarity = 7.25M
Volume =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.53/7.25
Volume = 0.073L
2. 0.035mol from a 1.25M
Mole = 0. 035mol
Molarity = 1.25M
Volume =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.035/1.25
Volume = 0.028L
3. Mole = 0.0013mol
Molarity = 0.090M
Volume =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.0013/0.090
Volume = 0.014L
So the whole point is that you need a abstract.
