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Korolek [52]
3 years ago
15

How much solar radiation is reflected back by clouds?

Chemistry
1 answer:
inna [77]3 years ago
5 0

Answer:

it's D

Explanation:

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Which part of homeostasis is this adorable puppy balancing out with his little stuffed animal buddy?
satela [25.4K]

Answer:

body temperature and energy

7 0
2 years ago
Determine the minimum work required by an air compressor. At the inlet the conditions are 150 kg/min, 125 kPa and 33 °C. At the
Firdavs [7]

Explanation:

The given data is as follows.

               MW = 29 g/mol,         C_{p} = 3.5 R

Formula to calculate minimum amount of work is as follows.

            W_{s} = C_{p}T_{1}[(\frac{P_{2}}{P_{1}})^{\frac{R}{C_{p}}} - 1]

                          = 3.5 \times 8.314 J/k mol \times 306 \times [(\frac{550}{125})^{\frac{1}{3.5}} - 1]

                          = 4.692 kJ/mol

Therefore, total work done will be calculated as follows.

                        Total work done = m \times W_{s}

Since, m = \frac{150 \times 10^{3}g/min}{29}. Therefore, putting these values into the above formula as follows.

            Total work done = m \times W_{s}

                                        = \frac{150 \times 10^{3}g/min}{29} \times 4.692 kJ/min      

                                       = 24268.96 kJ/min

It is known that 1 kJ/min = 0.0166 kW. Hence, convert 24268.96 kJ/min into kW as follows.

                   24268.96 kJ/min \times \frac{0.0166 kW}{1 kJ/min}                                                    

                   = 402.86 kW

Thus, we can conclude that the minimum work required by an air compressor is 402.86 kW.

6 0
3 years ago
Calculate the pH during the titration of 20.00 mL of 0.1000 M HNO2(aq) with 0.1000 M KOH(aq) after 13.27 mL of the base have bee
Slav-nsk [51]

Answer:

pH = 2.462.

Explanation:

Hello there!

In this case, according to the reaction between nitrous acid and potassium hydroxide:

HNO_2+KOH\rightarrow KNO_2+H_2O

It is possible to compute the moles of each reactant given their concentrations and volumes:

n_{HNO_2}=0.02000L*0.1000mol/L=2.000x10^{-3}mol\\\\n_{KOH}=0.1000mol/L*0.01327L=1.327x10^{-3}mol

Thus, the resulting moles of nitrous acid after the reaction are:

n_{HNO_2}=2.000x10^{-3}mol-1.327x10^{-3}mol=6.73x10^{-4}mol

So the resulting concentration considering the final volume (20.00mL+13.27mL) is:

[HNO_2]=\frac{6.73x10^{-4}mol}{0.01327L+0.02000L} =0.02023M

In such a way, we can write the ionization of this weak acid to obtain:

HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+

So we can set up its equilibrium expression to obtain x as the concentration of H3O+:

Ka=\frac{[NO_2^-][H_3O^+]}{[HNO_2]}\\\\7.1x10^{-4}=\frac{x^2}{0.02023M-x}

Next, by solving for the two roots of x, we get:

x_1=-0.004161M\\\\x_2=0.003451M

Whereas the correct value is 0.003451 M. Finally, we compute the resulting pH:

pH=-log(0.003451)\\\\pH=2.462

Best regards!

4 0
3 years ago
QUICK I WILL CHOOSE BRAILEST
viva [34]

Answer:

C

Explanation:

6 0
2 years ago
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Which elements are found in the compound NaOH? A. sodium, oxygen, and hydrogen B. nitrogen, oxygen, and hydrogen C. nitrogen, ar
Jet001 [13]
Sodium, Oxygen, and Hydrogen are found in NaOH. Na=Sodium, O=Oxygen, H=Hydrogen.
6 0
3 years ago
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