Explanation:
The given data is as follows.
MW = 29 g/mol,
= 3.5 R
Formula to calculate minimum amount of work is as follows.
![W_{s} = C_{p}T_{1}[(\frac{P_{2}}{P_{1}})^{\frac{R}{C_{p}}} - 1]](https://tex.z-dn.net/?f=W_%7Bs%7D%20%3D%20C_%7Bp%7DT_%7B1%7D%5B%28%5Cfrac%7BP_%7B2%7D%7D%7BP_%7B1%7D%7D%29%5E%7B%5Cfrac%7BR%7D%7BC_%7Bp%7D%7D%7D%20-%201%5D)
= ![3.5 \times 8.314 J/k mol \times 306 \times [(\frac{550}{125})^{\frac{1}{3.5}} - 1]](https://tex.z-dn.net/?f=3.5%20%5Ctimes%208.314%20J%2Fk%20mol%20%5Ctimes%20306%20%5Ctimes%20%5B%28%5Cfrac%7B550%7D%7B125%7D%29%5E%7B%5Cfrac%7B1%7D%7B3.5%7D%7D%20-%201%5D)
= 4.692 kJ/mol
Therefore, total work done will be calculated as follows.
Total work done = 
Since, m =
. Therefore, putting these values into the above formula as follows.
Total work done = 
=
= 24268.96 kJ/min
It is known that 1 kJ/min = 0.0166 kW. Hence, convert 24268.96 kJ/min into kW as follows.
= 402.86 kW
Thus, we can conclude that the minimum work required by an air compressor is 402.86 kW.
Answer:
pH = 2.462.
Explanation:
Hello there!
In this case, according to the reaction between nitrous acid and potassium hydroxide:

It is possible to compute the moles of each reactant given their concentrations and volumes:

Thus, the resulting moles of nitrous acid after the reaction are:

So the resulting concentration considering the final volume (20.00mL+13.27mL) is:
![[HNO_2]=\frac{6.73x10^{-4}mol}{0.01327L+0.02000L} =0.02023M](https://tex.z-dn.net/?f=%5BHNO_2%5D%3D%5Cfrac%7B6.73x10%5E%7B-4%7Dmol%7D%7B0.01327L%2B0.02000L%7D%20%3D0.02023M)
In such a way, we can write the ionization of this weak acid to obtain:

So we can set up its equilibrium expression to obtain x as the concentration of H3O+:
![Ka=\frac{[NO_2^-][H_3O^+]}{[HNO_2]}\\\\7.1x10^{-4}=\frac{x^2}{0.02023M-x}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BNO_2%5E-%5D%5BH_3O%5E%2B%5D%7D%7B%5BHNO_2%5D%7D%5C%5C%5C%5C7.1x10%5E%7B-4%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.02023M-x%7D)
Next, by solving for the two roots of x, we get:

Whereas the correct value is 0.003451 M. Finally, we compute the resulting pH:

Best regards!
Sodium, Oxygen, and Hydrogen are found in NaOH. Na=Sodium, O=Oxygen, H=Hydrogen.