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3 years ago

What is the value of x?

Mathematics

1 answer:

Bad White [126]3 years ago

7 0

Answer:

x = 4

Step-by-step explanation:

We are given a figure QRST which has two right angled triangles in it and we are to find the value of x.

To find x, we first need to find the side length of RT.

$sin 60=\frac{2\sqrt{3} }{RT}$

$RT = \frac{2\sqrt{3} }{sin 60}$

$RT = 4$

Now finding the value of x:

$tan 45 = \frac { x } { 4 }$

$x = tan 45 \times 4$

x = 4

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3 years ago

—2+7+(-4). Evaluate

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Answer:

Step-by-step explanation:

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Mr. Harris is packaging items to give to his students. He has 48 pencils and 30 notebooks. He wants each package to contain the

guapka [62]

Answer:

The maximum number of packages that can be made with each package have same number of each item is = 6

Step-by-step explanation:

Given:

Mr. Harris has 48 pencils and 30 notebooks.

To find the number of packages he can make with each package have same number of each item.

Solution:

Number of pencils = 48

Number of notebooks = 30

In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.

To find the G.C.F., we will list down the prime factors of each.

$48=2\times 2\times 2\times 2\times 3$

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We find that the G.C.F. = $2\times 3$ = 6

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3 years ago

Simplest form of 6×/15×

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2/5
I belive that’s the answer

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4 years ago

Given triangle ABC. Prove the three medians of triangle ABC intersect at a common point.

pychu [463]

Answer:

Let's try to render the first part of the proof a bit more legibly.

Point F is a midpoint of Line segment AB

Point E is a midpoint of Line segment AC

Draw Line segment BE

Draw Line segment FC by Construction

Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate

Draw Line segment AG by Construction

Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate

Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction

OK, now we continue. We need to prove some parallel lines; statement 4 lets us do so.

IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC -------- Midsegment Theorem

Now that we've shown some segments parallel we extend that to collinear segments.

III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC -------- Substitution

We have enough parallel lines to prove a parallelogram

I BGCH is a parallelogram -------- Properties of a Parallelogram (opposite sides are parallel)

Now we draw conclusions from that.

II Line segment BD ≅ Line segment DC -------- Properties of a Parallelogram (diagonals bisect each other)

Answer: IV III I II, second choice

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4 years ago