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andreyandreev [35.5K]
4 years ago
12

What is the molarity of a solution that contains 1.724 moles of H2SO4 in 2.50 L of solution? Show all your work.

Chemistry
1 answer:
RSB [31]4 years ago
6 0

Answer:

0.690 molar H 2 SO 4  or sulfuric acid

Explanation:

Molarity (M) =  1.724 mol  H 2 SO 4 / 2.50 L  =  0.6896 mol  H 2 SO 4 /L  =  0.690 mol H 2 SO 4 /L

(due to three significant figures in 2.50 L.)

The container for this solution would be labeled  0.690 M H 2 SO 4  and would be called  0.690 molar H 2 SO 4  or sulfuric acid.

The container for this solution would be labeled  0.690 M H 2 SO 4

and would be called  0.690 molar H 2 SO 4  or sulfuric acid.

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Calculate the final temperature of the system: A 50.0 gram sample of water initially at 100 °C and a 100 gram sample initially a
katrin2010 [14]

Answer:

The final temperature of the system is 42.46°C.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c\times (T_f-T_1)=-(m_2\times c\times (T_f-T_2))

where,

c = specific heat of water= 4.18J/g^oC

m_1 = mass of water sample with 100 °C= 50.0 g

m_2 = mass of water sample with 13.7 °C= 100.0 g

T_f = final temperature of system

T_1 = initial temperature of 50 g of water sample= 100^oC

T_2 = initial temperature of 100 g of water =13.7^oC

Now put all the given values in the given formula, we get

50.0 g\times 4.184 J/g^oC\times (T_f-100^oC)=-(100 g\times 4.184 J/g^oC\times (T_f-13.7^oC))

T_f=42.46^oC

The final temperature of the system is 42.46°C.

5 0
4 years ago
ALGEBRA 1 SEM 1
olganol [36]

Answer:

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Explanation:

6 0
3 years ago
When the pressure that a gas exerts
Ronch [10]

Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

5 0
3 years ago
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True or false: The force exerted onto an object must be perpendicular to the displacement if work is to be considered done.
RUDIKE [14]

Answer:

its letter B. false

Explanation:

bjchakfbhc

4 0
3 years ago
PLEASE I NEED HELP I DONT KNOW THE ANSWER. Fill out the highlighted areas. I will mark brainliest to the first person
MariettaO [177]

Answer:

I think

Explanation:

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3 years ago
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