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Romashka-Z-Leto [24]
3 years ago
9

Numatoms is initially 7. what is numatoms after: numatoms += 5?

Physics
1 answer:
Neporo4naja [7]3 years ago
8 0
S s. S s abbs s sbsbs z sbs
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What is the speed of a wave frequency of 300hz and a wavelength of 25M
tia_tia [17]

Answer:

7500 m/s

Explanation:

We can use the equation velocity of a wave equals wavelength times  frequency.  Therefore, v = wavelength*f = (25 m)(300 Hz) =  m/s7,500

8 0
4 years ago
A wire is formed into a circle having a diameter of 19.0 cm and placed in a uniform magnetic field of 3.40 mT. The wire carries
nikklg [1K]

Answer:

Explanation:

Radius = 9.5 x 10⁻² m

area of circle = 3.14 x (9.5 x 10⁻² )²

A = 283.38 x 10⁻⁴ m²

magnetic moment = area x current

M = 283.38 x 10⁻⁴ x 5

= 1416.9 x 10⁻⁴  Am²

Torque = MBsinθ

M is magnetic moment , B is magnetic field .

Max torque = 1416.9 x 10⁻⁴  x 3.4 x 10⁻³ , for θ = 90

= 4817.46 x 10⁻⁷

= 481.7 x 10⁻⁶

= 481.7 μ J

Energy = - MBcosθ

Max  energy  when θ = 180

MB = 4817.46 x 10⁻⁷ J

Min energy = - 4817.46 x 10⁻⁷  for θ = 0

7 0
3 years ago
Urgently!
adelina 88 [10]

Answer:

0.003333 s to 0.000125s or from 3.33ms to 0.125ms wher m is for milli

1.1m to 0.04125 m

Explanation:

T= 1/f=

if f= 300Hz then T = 1/300 =0.003333 s

if f= 8000 then T= 1/8000 = 0.000125s

now v=f×wave length

or wavelength = speed/ frequency

when f = 300 Hz

wavelength = 330/300=1.1 m

wavelength = 330/8000 = 0.04125m

note : i have taken speed of sound as 330 m/s you can take any value given in between 330m/s to 340m/s

6 0
3 years ago
Why unit of pascal is called derived unit?​
Annette [7]

Answer:

This is because it is derived from newtons and metres as shown in the expression;

Explanation:

pressure =  \frac{force}{area} \\  P= \frac{F}{A}  \\ P= \frac{newtons}{ {m}^{2} }  \\  = pascals

5 0
3 years ago
Read 2 more answers
If the dielectric constant is 14.1, calculate the ratio of the charge on the capacitor with the dielectric after it is inserted
Lady bird [3.3K]

Answer:

\frac{Q}{Q_0}=1

Explanation:

Capacitance is defined as the charge divided in voltage.

C=\frac{Q}{V}(1)

Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:

V=\frac{V_0}{k}

Where k is the dielectric constant and V_0 the voltage of the capacitor without a dielectric

The capacitance with a dielectric between the capacitor plates is given by:

C=kC_0

Where k is the dielectric constant and C_0 the capacitance of the capacitor without a dielectric. So, we have:

Q=CV\\Q=kC_0\frac{V_0}{k}\\Q=C_0V_0\\Q_0=C_0V_0\\Q=Q_0\\\frac{Q}{Q_0}=1

Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.

7 0
3 years ago
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