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Kay [80]
2 years ago
12

An astronaut in a spacesuit has a mass of 100 kilograms. What is the weight of this astronaut on the surface of the Moon where t

he strength of gravity is approximately 1/6 that of Earth?
Physics
1 answer:
arlik [135]2 years ago
3 0
Weight = (mass) x (gravity) = (100 kg) x (1.62 m/s^2) = 162 newtons.
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Consider the following situations:
Snezhnost [94]

Answer:

Though no question is specified here but let analyzed experiences of each

Explanation:

1. Required a force to stop it (Law of inertial). Constant acceleration

2. will have reduced acceleration (deceleration)

3. Uniform acceleration may set in. it accelerate

4. maximized it speed since no friction affect it motion

5. accelerating. Vo=0 and V gradually increased

6. less or no friction opposes the motion

7. It  experience reduce motion based on air friction

8. constant acceleration due to gravity

9. g can be a bit affected but still about equal

4 0
3 years ago
Keeping in mind that not all flasks are vacuum, Please help me explain how other flasks prevent heat loss?​
lidiya [134]
The silver coating on the inner bottle prevents heat transfer by radiation, and the vacuum between its double wall prevents heat moving by convection. The thinness of the glass walls stops heat entering or leaving the flask by conduction.
4 0
2 years ago
John sees Linda Running towards him at 11 m/s. while running, Linda throws a ball at 5m/s. what is the speed of the ball as obse
Ilia_Sergeevich [38]
11m/s Bc of the fact that he sees her running at 11m/s
7 0
2 years ago
How does the electric force between two charged particles change if the distance between them is increased by a factor of 2
mart [117]
Electric force will increase
6 0
3 years ago
When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g
BartSMP [9]

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

d sin\theta = m\lambda

Here,

d = Distance between Slits

m = Order of the fringes

\lambda = Wavelength

\text{Spacing between adjacent lines} = d = 4926nm

\text{Wavelength of light} = \lambda = 656nm

Rearranging to find the angle,

sin\theta = \frac{m\lambda}{d}

\theta = sin^{-1}(\frac{m\lambda}{d})

\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})

\theta = 32.19\°

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

3 0
3 years ago
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