Ask question

Ask question

All categories

3 years ago

12

An astronaut in a spacesuit has a mass of 100 kilograms. What is the weight of this astronaut on the surface of the Moon where t

he strength of gravity is approximately 1/6 that of Earth?

1 answer:

arlik [135]3 years ago

3 0

Weight = (mass) x (gravity) = (100 kg) x (1.62 m/s^2) = 162 newtons.

You might be interested in

Which dinosaur had teeth that measured six inches

Rudik [331]

Answer:

Tyrannosaurus rex

7 0

3 years ago

Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is comple

lisov135 [29]

Answer:

Answer to the above question is given as follows:

(1) Forward

(2) Increases

(3) Small, No Whiplash

Explanation:

3 0

3 years ago

Read 2 more answers

Which of these forms due to the force of compression?

Georgia [21]

Answer:

anticline

Explanation:

hope u will understand

4 0

3 years ago

Read 2 more answers

A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this

wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

$r=r_o\times A^{\frac{1}{3}}$

$r_o=1.25 \times 10^{-15} m$ = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

$r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}$

$r=4.6656\times 10^{-15} m=4.6656 fm$

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) $F=k\times \frac{q_1q_2}{a^2}$

k= $9\times 10^9 N m^2/C^2$ = Coulombs constant

$q_1,q_2$ = charges kept at distance 'a' from each other

F = electrostatic force between charges

$q_1=+1.602\times 10^{-19} C$

$q_2=+1.602\times 10^{-19} C$

Force of repulsion between two protons on opposite sides of the diameter

$a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m$

$F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}$

$F=2.6527 N$

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0

3 years ago

Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t

Lady_Fox [76]

Answer:

Sound wave is a longitudinal wave that propagates in a medium

Explanation:

<em>Part A:</em> (C) Sound wave is propagation of pressure fluctuations in a medium.

<em>Part B: </em>(C) Pressure fluctuations travel along the direction of propagation of the sound wave.

<em>Part C: </em>(A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.

5 0

3 years ago