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prisoha [69]
3 years ago
9

How much energy (in kW-h) does a 900 Watt stove use in a week if it is used for 1.5 hours each day?

Physics
1 answer:
ioda3 years ago
3 0

Answer:

9.45 kWh

Explanation:

Energy = Power × time

E = 900 W × (1.5 h/day × 7 day)

E = 9450 Wh

E = 9.45 kWh

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Sledding down a hill, you are traveling at 10 m/s when you reach the bottom. You (inertia 80 kg ) then move across horizontal sn
RSB [31]

Answer:

V = 0.32 m /s

Explanation:

Momentum of the man on the sledge along with sledge

= (80+8) x 10 = 880 kg. m/s When the man jumps off the sledge , the velocity of the sledge will remain intact at 10 m/s

When the sledge hits the boulder and bounces back the momentum of the sledge - boulder system will remain conserved .

change in momentum of sledge = 8 x (10 +6 )

= 128  kg m/s

Change in the momentum of boulder

= 400 V -0

= 400V

400V = 128

V = 0.32 m /s

5 0
3 years ago
A parallal capacitor consists of two Squere plates each of Side 25cm, 3. Omm apart. If a potential difference of 2000volts is ap
Lana71 [14]

Answer:poop

Explanation:

poop

7 0
3 years ago
a model rocket is launched at an angle of 55 to the horizontal with a momentum of 20 kg-m/. If the vertical component of its vel
den301095 [7]
Given:\\ \alpha =55^\circ\\p=20kg\cdot  \frac{m}{s} \\v_v=40 \frac{m}{s} \\\\Find:\\m=?\\\\Solution:\\\\p_v=mv_v\Rightarrow m= \frac{p_v}{v_v} \\\\ \frac{p_v}{p} =\cos  \alpha \Rightarrow p_v=p\cos  \alpha \\\\m= \frac{p\cos  \alpha }{v_v} \\\\m= \frac{20kg\cdot  \frac{m}{s} \cdot \cos 55^\circ }{40 \frac{m}{s} } \approx 0.287kg=287g
4 0
3 years ago
When was the Federation Internationale de Football Association ( F.I.F.A) founded ?
Fantom [35]

Answer:

c - May 21, 1904

Federation lnternational de Football Association was established on May 21, 1904

Explanation:

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3 0
3 years ago
A tellurium-sapphire laser can produce light at wavelength of 800 nm in ultrashort pulses that last only 4.00x10-15s (4.00 femto
natka813 [3]

The speed of light and the propagation of errors allows to find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is: f = 3.7 10¹⁴ Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

a) The speed of a wave is related to its wavelength and frequency.

           c = λ f

           f = \frac{c}{\lambda}

Where c is the speed of light, λ the wavelength and f the frequency.

They indicate that the wavelength is λ = 800 nm = 800 10⁻⁹ m, the speed of light is a constant c = 2.99 10⁸ m/s.

         f = \frac{2.99 \ 10^8}{800 \ 10^{-9}}  

         F = 3.7 10¹⁴ Hz

b) Planck's equation states that the energy is proportional to the frequency of the radiation.

         E = h f

Where E is the energy, h the Planck constant and f the frequency.

         E = 6.63 10⁻³⁴  3.7 10¹⁴

         E = 2.46467 10⁻¹⁹ J

The uncertainty or error is the fluctuation that a magnitude may have due to the precision in the measurements, when the magnitude is calculated by some formula, the propagation of these uncertainties must be carried out.

         

        Δm = ∑   \sum \frac{dm}{dx_i}  | \Delta x_I|  

the expression for energy is:

        E = \frac{hc}{\lambda }  

        \Delta E = \frac{dE}{d \lambda} |D\lambda |  

        \Delta E = \frac{h c }{\lambda^2 } |\Delta \lambda |

When the error in the measured magnitude is not explicitly indicated, we assume that the error is in the last digit written, therefore

         Δλ = ± 1 nm = ± 1 10⁻⁹ m

We calculate.

        \Delta E = \frac{6.63 \ 10^{-34} \ 2.99 \ 10^8 }{(800 \ 10^{-9})^2} 1 \ 10^{-9}  

        ΔE = 3.1 10⁻²² J

the error is given with a significant figure.

        ΔE = 3 10⁻²² J = 0.004 10⁻¹⁹ J

The result of the energy is:

        E = (2.465 ± 0.004) 10⁻¹⁹ J

In conclusion, using the speed of light and the propagation of errors, we can find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is; f = 3.7 1014 Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

Learn more here:  brainly.com/question/15557220

3 0
3 years ago
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