Answer:
8.96 mol of HCl is produced.
Explanation:
CH₄ + 4Cl₂ → CCl₄ + 4HCl 80% yield
CCl₄ + 2HF → CCl₂F₂ + 2HCl 80% yield
The first reaction:
1 mol CH₄ ____ 4 mol HCl 1 mol CH₄ ____ 1 mol CCl₄
2 mol CH₄ ____ x 2 mol CH₄ ____ x
x = 8 mol HCl x = 2 mol HCl
The first reaction would lead to 8 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x8 = 6.4 mol HCl
The same applies for CCl₄: 0.8x2 = <u>1.6 mol CCl₄</u>
<u />
The second reaction:
1 mol CCl₄ ____ 2 mol HCl
1.6 mol CH₄ ____ x
x = 3.2 mol HCl
The second reaction would lead to 3.2 mol of HCl, but as its yield is 80%, the total ammount of HCl produced is 0.8x3.2 = 2.56 mol HCl
Therefore, considering both reactions, 8.96 mol of HCl is produced.
Answer:
D.
Explanation:
I took this test as a freshman and this was the only question of 4 that I can remember
Because of gravity not pulling you down
Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
Answer:
Meiosis produces haploid cells (gametes), which contain single chromosomes, or on-half the number of chromosomes in diploid cells. When a sperm and an egg join, the single chromosomes pair up, which results in genetic diversity in the offspring
