Answer plzzzz im begging

Diffusion occurs due to differences in _____. A) size B) concentration C) temperature D) collisions

larisa86 [58]

Diffusion occure due to temperature

4 0

2 years ago

What is the concentration (M) of CH3OH in a solution prepared by dissolving 12.5 g of CH3OH in sufficient water to give exactly

timurjin [86]

Answer:

1.7 M

Explanation:

Concentration is the number of moles of solute dissolved in 1 L of solution

Concentration = number of moles of solute / volume of solution

Number of moles of solute needs to be calculated first

Mass of methanol - 12.5 g

Molar mass of methanol - 32 g/mol

Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol

Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L

Concentration is 1.7 M

6 0

3 years ago

What does the octet rule state that explains why atoms bond

dezoksy [38]

The octet rule is a chemical rule of thumb that reflects observation that atoms of main-group elements tend to combine in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas. The rule is especially applicable to carbon, nitrogen, oxygen, and the halogens, but also to metals such as sodium or magnesium.

The valence electrons can be counted using a Lewis electron dot diagram as shown at the right for carbon dioxide. The electrons shared by the two atoms in a covalent bond are counted twice, once for each atom. In carbon dioxide each oxygen shares four electrons with the central carbon, two (shown in red) from the oxygen itself and two (shown in black) from the carbon. All four of these electrons are counted in both the carbon octet and the oxygen octet.

4 0

3 years ago

Read 2 more answers

A. Element X has a

vlabodo [156]

The mass is written as a superscript and the charge is written as a subscript in the isotope notation of element X as follows $\frac{292}{119} X$ .

The isotope notation may also be called the nuclear notation of an element. It helps us to identify what element is represented. It usually comprises of the atomic mass of the element written as a superscript and then the atomic number or charge written as a subscript.

In this case, we have an element with an mass of 292 amu and charge of 119. In this case, the isotope notation of element X is $\frac{292}{119} X$ .

Learn more: brainly.com/question/5838915

8 0

2 years ago

Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-lif

elixir [45]

Answer:

Hello your question is poorly written below is the well written question

Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5 billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth

Answer : 140 billion years

Explanation:

Given that :

U-238 h1/2 = 4.5 billion years

U-235 h1/2 = 700 million years

At the beginning both Isotopes where present in equal amount

Determine the T years before the amount of Uranium decays to Half

T = ? N'2 = N1 / 2

we know that N = No ( 1/2 )^h where h = time / half-life time

attached below is the detailed solution of the given problem

6 0

2 years ago