Answer: C
Explanation: They both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, Golgi apparatus, lysosomes, and peroxisomes.
Answer:
when the rates of the forward and reverse reactions are equal
Explanation:
In a chemical system, the reaction reaches a dynamic equilibrium when the rate of formation of product equals the rate of formation of reactants. This implies that both the forward and revered(backwards) reaction are occurring at the same rate.
Answer: The atomic weight of the metal would be 85.47.
Explanation:
Mass of isotope 1 of metal = 84.9118
% abundance of isotope 1 of metal = 72.15% = 
Mass of isotope 2 of metal= 86.9092
% abundance of isotope 2 of metal = 27.85% = 
Formula used for average atomic mass of an element :
![A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2884.9118%29%5Ctimes%20%5Cfrac%7B72.15%7D%7B100%7D%29%2B%2886.9092%29%5Ctimes%20%5Cfrac%7B27.85%7D%7B100%7D%5D%5D)
Therefore, the atomic weight of the metal would be 85.47.
Molecules in the paper react differently with Hydronium and Hydroxide.
pH paper deals with acidity and basicity of something. You are correct in thinking that A is the answer. Always go with your gut. don't be like me when I was in college who always second guessed my answers. Good luck with chemistry.
Answer:
1. Hydrogen will diffuse faster.
2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1
Explanation:
Let the rate of diffusion of hydrogen gas, H2 be R1
Let the molar mass of H2 be M1
Let the rate of diffusion of the unknown gas be R2.
Let the molar mass of the unknown gas be M2.
Molar mass of H2 (M1) = 2x1 =2g/mol
Molar mass of unknown gas (M2) = 16 times that of H2
= 16 x 2 = 32g/mol
1. Determination of the gas that will diffuse faster. This is illustrated below:
R1/R2 = √(M2/M1)
R1/R2 = √(32/2)
R1/R2 = √16
R1/R2 = 4
Cross multiply
R1 = 4R2
From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).
Therefore, hydrogen will diffuse faster.
2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;
R1/R2 = 4
Therefore, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is:
4 : 1
