Question

If someone who is good at this can help me

Answer 1

Answer:

1. C—N Bond of 1, C≡N Bond order 3, C=N Bond Order 2

(least BDE) C—N < C=N < C≡N (Most BDE)

2. Br

   C

   P

   Be

3.  (least polar) O-F, C-F, Be-F (Most polar)

    (Least) Br-Cl, C-Cl, Be-Cl (Most)

    (least)C-H, C-Cl, C-O (most)

Explanation:

For lewis, please google them