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3 years ago

If someone who is good at this can help me

Chemistry

1 answer:

xz_007 [3.2K]3 years ago

6 0

Answer:

1. C—N Bond of 1, C≡N Bond order 3, C=N Bond Order 2

(least BDE) C—N < C=N < C≡N (Most BDE)

2. Br

3. (least polar) O-F, C-F, Be-F (Most polar)

(Least) Br-Cl, C-Cl, Be-Cl (Most)

(least)C-H, C-Cl, C-O (most)

Explanation:

For lewis, please google them

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3 years ago

Match the following numbers with the correct number of significant digits they possess. Answers may repeat. (4 points)

mezya [45]

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8 0

3 years ago

3Al + 3 NH4ClO4 ---> Al2O3 + AlCl3 + 3 NO + 6H20

Tresset [83]

Answer:

9.63 L of NO

Explanation:

We'll begin by calculating the number of mole in 50.0 g of NH₄ClO₄. This can be obtained as follow:

Mass of NH₄ClO₄ = 50 g

Molar mass of NH₄ClO₄ = 14 + (4×1) + 35.5 + (16×4)

= 14 + 4 + 35.5 + 64

= 117.5 g/mol

Mole of NH₄ClO₄ =?

Mole = mass /molar mass

Mole of NH₄ClO₄ = 50/117.5

Mole of NH₄ClO₄ = 0.43 mole

Next, we shall determine the number of mole of NO produced by the reaction of 50 g (i.e 0.43 mole) of NH₄ClO₄. This can be obtained as follow:

3Al + 3NH₄ClO₄ –> Al₂O₃ + AlCl₃ + 3NO + 6H₂O

From the balanced equation above,

3 moles of NH₄ClO₄ reacted to produce 3 moles of NO.

Therefore, 0.43 mole of NH₄ClO₄ will also react to produce 0.43 mole of NO.

Finally, we shall determine the volume occupied by 0.43 mole of NO. This can be obtained as follow:

1 mole of NO = 22.4 L

Therefore,

0.43 mole of NO = 0.43 × 22.4

0.43 mole of NO = 9.63 L

Thus, 9.63 L of NO were obtained from the reaction.

6 0

2 years ago

Write chemical equation for the following reactions. Indicate physical states and write net ionic equations. If no reaction indi

iren [92.7K]

There is no reaction.

Molecular equation :

K₂CO₃(aq) + 2NH₄Cl(aq) ⟶ 2KCl(aq) + (NH₄)₂CO₃(aq)

Ionic equation :

2K⁺(aq) + CO₃²⁻(aq) + 2NH₄⁺(aq) +2Cl⁻(aq) ⟶ 2K⁺(aq) + 2Cl⁻(aq) + 2NH₄⁺(aq) + CO₃²⁻(aq)

Net ionic equation :

Cancel all ions that appear on both sides of the reaction arrow (underlined).

2K⁺(aq) + CO₃²⁻(aq) + 2NH₄⁺(aq) +2Cl⁻(aq) ⟶ 2K⁺(aq) + 2Cl⁻(aq) + 2NH₄⁺(aq) + CO₃²⁻(aq)

All ions cancel. There is no net ionic equation.

7 0

3 years ago