Question

A net force of 5.0 newtons moves a 2.0-kilogram object a distance of 3.0 meters in 3.0 seconds. how much work is done on the object?

Answer 1

Answer: The work done on the object is 15 J

Explanation:

Work is defined as the force that is causing the movement or displacement of an object.

Mathematically,

$W=F\times d$

where,

W = work done on the object = ?

F = Force applied on the object = 5.0 N

d = displacement = 3.0 m

Putting values in above equation, we get:

$W=5.0N\times 3.0m\\\\W=15J$

Hence, the work done on the object is 15 J

Answer 2

We know that the work formula is calculated as force by distance:
    W = F * d
   W = 5 * 3 = 15 N*m = 15 Joules

   So the work done on the object is 15 joules