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Diano4ka-milaya [45]
3 years ago
15

An object is dropped from a 145 m ledge. How fast it is moving just before it hits the ground

Physics
1 answer:
LuckyWell [14K]3 years ago
8 0
D = 1/2 x g × t²
145 = 1/2 × 9.8 × t²
t = 5.4 s
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u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

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<u>Now the horizontal component of velocity:</u>

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<u>The vertical component of the velocity:</u>

v_y=v.sin\ \theta

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<u>Time taken to reach this height:</u>

v'=u'-g.t'

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<u>We observe that </u>t>t'<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

\Delta t=t-t'

\Delta t=1.0642-1.0469

\Delta t=0.0173\ s

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