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Diano4ka-milaya [45]
3 years ago
15

An object is dropped from a 145 m ledge. How fast it is moving just before it hits the ground

Physics
1 answer:
LuckyWell [14K]3 years ago
8 0
D = 1/2 x g × t²
145 = 1/2 × 9.8 × t²
t = 5.4 s
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Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

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Given;

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First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

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Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

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Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

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