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Diano4ka-milaya [45]
3 years ago
13

•. Parking orbit is -

Physics
2 answers:
notsponge [240]3 years ago
7 0

Answer:

Parking orbit is -

a. The path along which a plane travels

b. Orbit of a polar satellite

c. Orbit of geostationary satellite

d. Orbit of the earth.

Explanation:

sergeinik [125]3 years ago
7 0
A b and c because I actually don’t know why but I did just finish that test and I guessed right
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solid molecules are packed closely and liquid molecules are losely packed

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A light bulb uses 0.5 amperes from a source of 120 volts. How much power is used by the bulb? 
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Power = voltage(V) * current(I)

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Which of the following best describes the energy transformations that take place when a battery-powered dvd player is used to wa
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A 2.10 cm × 2.10 cm square loop of wire with resistance 1.30×10−2 Ω has one edge parallel to a long straight wire. The near edge
Troyanec [42]

Answer:

I_{l} =44.84 \mu A

Explanation:

given,

side of square loop = a = 2.10 cm

Resistance of the wire =  1.30×10⁻² Ω  

Length of the loop = c = 1.10 cm

rate of increasing current = 130 A/s

\phi = \dfrac{\mu_0Ib}{2\pi}(ln(\dfrac{c+a}{c}))

\dfrac{d\phi}{dt}= \dfrac{\mu_0b}{2\pi}\dfrac{dI}{dt}(ln(\dfrac{c+a}{c}))

I_{l} = \dfrac{V}{R}

I_{l} = \dfrac{1}{R}\dfrac{d\phi}{dt}

I_{l} = \dfrac{1}{R}\dfrac{\mu_0b}{2\pi}\dfrac{dI}{dt}(ln(\dfrac{c+a}{c}))

I_{l} = \dfrac{1}{1.3 \times 10^{-2}}\dfrac{4\pi\times 10^{-7}\times 0.021}{2\pi}\times 130\times (ln(\dfrac{0.011+0.021}{0.011}))

I_{l} =44.84 \times 10^{-6}\A

I_{l} =44.84 \mu A

3 0
3 years ago
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