0.7 mol of H⁺ ions are present in 2.8 l of 0.25 m hydrobromic acid solution.
Hydrobromic acid is a strong acid, we can assume that all acid molecules dissociate completely to yield H+ ions and dissociated anion.
<h3>The equation for the dissociation of HBr :</h3>
Hbr <em>(s) → </em>H⁺ <em>(aq) </em>+ Br⁻<em> (aq)</em>
<em></em>
moles H⁺ = (
) ( 
) (
) ( 
)
= 0.7 mol
Therefore, 0.7 mol of H⁺ ions is present.
Learn more about H⁺ ions here:
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The answer is
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</span>Temperature and silica content determine the viscosity of magma.
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Have a nice day.</span>
Methane (CH4) = 1 carbon atom, 4 hydrogen
Sulphuric Acid (H2SO4) = 2 hydrogen atoms, 1 sulfur and 4 oxygen.
Answer:
a) Keq = 4.5x10^-6
b) [oxaloacetate] = 9x10^-9 M
c) 23 oxaloacetate molecules
Explanation:
a) In the standard state we have to:
ΔGo = -R*T*ln(Keq) (eq.1)
ΔGo = 30.5 kJ/moles = 30500 J/moles
R = 8.314 J*K^-1*moles^-1
Clearing Keq:
Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6
b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])
4.5x10^-6 = ([oxaloacetate]/(0.20*10)
Clearing [oxaloacetate]:
[oxaloacetate] = 9x10^-9 M
c) the radius of the mitochondria is equal to:
r = 10^-5 dm
The volume of the mitochondria is:
V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L
1 L of mitochondria contains 9x10^-9 M of oxaloacetate
Thus, 4.18x10^-42 L of mitochondria contains:
molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
