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Harlamova29_29 [7]
3 years ago
5

What us halfway between 7.5 and 10

Chemistry
1 answer:
serg [7]3 years ago
6 0
10-7.5=2.5, 2.5/2=1.25, 7.5+1.25=8.75
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Which half-reaction correctly represents oxidation?
Leokris [45]

Answer: Mg\rightarrow Mg^{2+}+2e^- represents oxidation.

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Example: Mg\rightarrow Mg^{2+}+2e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Example: Mg^{2+}+2e^-\rightarrow Mg

Mg\rightarrow Mg^{2+}+2e^- represents oxidation.

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3 years ago
What is a sign that a person may be abusing drugs?
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Answer:

answer is a because drugs do so to the person.

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3 years ago
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Why do you require an acid catalyst to make an ester? Why not just mix acid and alcohol? Describe an alternate method of making
djverab [1.8K]

Answer:Acid catalyst is needed to increase the electrophilicity of Carbonyl group of Carboxylic acid as alcohol is a weak nucleophile.

Alternatively esters can be synthesised by converting carboxylic acid into acyl chloride using thionyl chloride(SOCl_{2} and then further treating acyl chloride with alcohol.

Carboxylic acid and esters can be easily distinguished on the basis of IR as carboxylic acid would contain a broad intense peak in 2500-3200cm_{-1} corresponding to OH stretching frequency whereas esters would not contain any such broad intense peak.

Alcohol and esters can also be distinguished using IR as alcohols would contain a broad intense peak at around 3200-3600cm_{-1}

Explanation: For the synthesis of esters using alcohol and carboxylic acid we need to add a little amount of acid in the reaction . The acid used here increases the electrophilicity of carbonyl carbon and hence makes it easier for a weaker nucleophile like alcohol to attack the carbonyl carbon of acid.

The oxygen of the carbonyl group is protonated using the acidic proton which  leads to the generation of positive charge on the oxygen. The positive charge generated is delocalised over the whole acid molecule and hence the electrophilicity of carbonyl group is increased. Kindly refer attachment for the structures.

If we simply mix the acid and alcohol then no appreciable reaction would take place between them and ester formation would not take place because the carboxylic acid in that case is not a good electrophile whereas alcohol is also not a very strong nucleophile which can attack the carbonyl group.

Alternatively we can use thionyl chloride or any other reagent which can convert the carboxylic acid into acyl chloride. Acyl chloride is very elctrophilic and alcohol can very easily attack the acyl chloride and esters could be synthesized.

The carboxylic acid and ester can very easily be distinguished on the basis of broad intense OH stretching frequency peak at around 2500-3200cm_{-1} . The broad intense OH stretching frequency peak is present in carboxylic acids as they contain OH groups and absent in case of esters .

Likewise esters and alcohols can also be distinguished on the basis IR spectra as alcohols will have broad intense spectra  at around 3200-3600cm_{-1}corresponding to OH stretching frequency whereas esters will not have any such peak. Rather esters would be having a Carbonyl stretching frequency at around 1720-1760

4 0
3 years ago
1) Какое количество вещества Феррум (III) гидроксида вступает в реакцию с 15 г сульфатной кислоты?
EleoNora [17]

i dont speak russian sorry

3 0
3 years ago
part of the SO2 that is introduced into the atmosphere by combustion of sulfur containing compounds ends up being converted to s
alisha [4.7K]

Answer:

5 mol.

Explanation:

Equation of the reaction

2SO2 + 2H2O + O2 --> 2H2SO4

By stoichiometry, 2 moles of SO2 reacted with 2 moles of water and 1 mole of O2 to give 2 mole of sulphuric acid.

Number of moles:

5.0 mol SO2

4.0 mol O2

20.0 mol H2O

Calculating the limiting reagent,

5 mol of SO2 * 1 mol of O2/2 mol of SO2

= 2.5 mol of O2(4 mol of O2 is present)

5 mol of SO2 * 2 mol of H2O/2 mol of SO2

= 5 mol of H2O(20 mol of H2O)

SO2 is the limiting reagent.

Therefore, number of moles of H2SO4 = 5 mol of SO2 * 2 mol of H2SO4/2 mol of SO2

= 5 mol of H2SO4.

5 0
3 years ago
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