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kati45 [8]
3 years ago
12

Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce

55.0 g of Hg? Note: 4 Hg2S + 4 CaO -> 8 Hg + 3 CaS + 1 CaSO4
Chemistry
1 answer:
OLga [1]3 years ago
4 0
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!
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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
mario62 [17]

Given parameters:

Volume of CuSO₄ = 250mL

Concentration of CuSO₄ = 2.01M

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Mass of CuSO₄.5H₂O = ?

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Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

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Take 250mL to L so as to ensure uniformity of units;

           Volume  = 250 x 10⁻³L

  Input the parameters and solve for number of moles;

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From the equation;

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So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

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3 years ago
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Answer:

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