At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
<h3>
What is
Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 2moles
- Initial volume v₁ = 13.9L
- Final amount of gas n₁ = 3moles
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (13.9L × 3moles) / 2moles
V₂ = 41.7molL / 2mol
V₂ = 20.85L
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
Learn more about Avogadro's law here: brainly.com/question/15613065
#SPJ1
Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
We know that
pH = -log[H+]
the pH value falls in between 0- 7 for acids
As the pH value increases the concentration of [H+] increases.
similarly as the value of pH approaches 0, the concentration of H+ increases
The solution said to become more acidic
Also
[H+] X [OH-] = 10^-14
Thus pH + pOH = 14
hence the concentration of OH- decreases as the pH approaches zero
