NH4I (aq) + KOH (aq) in chemical equation gives
NH4I (aq) + KOH (aq) = KI (aq) + H2O(l) + NH3 (l)
Ki is in aqueous state H2o is in liquid state while NH3 is in liquid state
from the equation above 1 mole of NH4I (aq) react with 1 mole of KOH(aq) to form 1mole of KI(aq) , 1mole of H2O(l) and 1 Mole of NH3(l)
Answer:
Protons 4 or 5 are most acidic.
Explanation:
As mentioned there are four types of hydrogen in Hexane-2,4-dione.
The numbering are shown in the figure for your better understanding.
As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).
Thus protons 4 or 5 are most acidic.
Answer:
no
Explanation:
you would need an electron microscope to see atoms.
Answer:
B
Explanation:
elements in the same group are most similiar