When you strike two tuning forks simultaneously, you hear three beats per second. The frequency of the first tuning fork is 440
2 answers:
Answer:4
Explanation:
Given
Frequency of beats is 3 beats per second
Frequency of first tuning fork is
Beat frequency is difference in the frequency of tuning forks i.e.
either or
so
or
so there is not enough information given to decide.
Answer:
The frequency of the second tuning fork is 437 Hz.
(2) is correct option.
Explanation:
Given that,
Frequency of first tuning fork = 440 Hz
Frequency of beat = 3 Hz
We need to calculate the frequency of the second tuning fork
Using formula of beat frequency
Put the value in to the formula
Hence, The frequency of the second tuning fork is 437 Hz.
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Answer:
f = q
Explanation:
In the attachment we can see a diagram of the parallel rays.
The dotted line represents the normal to the mirror surface
These rays when reflected using the constructor equation
where p and q are the distance to the object and the image respectively.
Since the rays are parallel P = inf
1 / f = 1 / inf + 1 / q
f = q
this means that all the rays focus on one focal point.
Answer:
19.5°
Explanation:
The energy of the mass must be conserved. The energy is given by:
1)
where m is the mass, v is the velocity and h is the hight of the mass.
Let the height at the lowest point of the be h=0, the energy of the mass will be:
2)
The energy when the mass comes to a stop will be:
3)
Setting equations 2 and 3 equal and solving for height h will give:
4)
The angle ∅ of the string with the vertical with the mass at the highest point will be given by:
5)
where l is the lenght of the string.
Combining equations 4 and 5 and solving for ∅:
6)