Question

When you strike two tuning forks simultaneously, you hear three beats per second. The frequency of the first tuning fork is 440 Hz. What is the frequency of the second tuning fork? 1. 446 Hz 2. 437 Hz 3. 443 ㎐ 4. not enough information is given to decide

Answer 1

Answer:4

Explanation:

Given

Frequency of beats is 3 beats per second

Frequency of first tuning fork is $f_1=440\ Hz$

Beat frequency is difference in the frequency of tuning forks i.e.

either $f_1-f_2$ or $f_2-f_1 =3$

so $f_2=3+440=443\ Hz$

or

$f_2=440-3=437\ Hz$

so there is not enough information given to decide.

Answer 2

Answer:

The frequency of the second tuning fork is 437 Hz.

(2) is correct option.

Explanation:

Given that,

Frequency of first tuning fork = 440 Hz

Frequency of beat = 3 Hz

We need to calculate the frequency of the second tuning fork

Using formula of beat frequency

$beat\ frequency=f_{1}-f_{2}$

Put the value in to the formula

$3=440-f_{2}$

$f_{2}=440-3$

$f_{2}=437\ Hz$

Hence, The frequency of the second tuning fork is 437 Hz.