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kati45 [8]
2 years ago
9

What affects fuel consumption in automobiles?

Physics
1 answer:
maksim [4K]2 years ago
4 0

Answer:

A and C

Explanation:

drag (the area of lower air pressure behind the car when moving) and mostly air resistance (the work to push the air in front of us away to move through - the faster we go, the stronger the air resists to move aside).

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A meter scale is placed along the axis of a convex mirror of focal length 25cm, its nearer end being at a distance of 50cm. calc
swat32

Explanation:

this is the answer.....................

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6 0
3 years ago
An electric field is described by the vector e=yj -xi. what is the electric flux through a rectangular box in the x-z plane that
Varvara68 [4.7K]

The flux of \vec E = -x\,\vec\imath + y\,\vec\jmath is given by the surface integral

\displaystyle \iint_S \vec E \cdot d\vec\sigma

where S is the given square region, which we can parameterize by

\vec s(x, z) = x\,\vec\imath + z\,\vec k

with 0\le x\le 1 and 0\le z\le 1. The area element is

d\vec\sigma = \vec n \, dx\,dz

where \vec n is the normal vector to S. Depending on the orientation of S, this vector could be

\vec n = \dfrac{\partial\vec s}{\partial x} \times \dfrac{\partial\vec s}{\partial z} = -\vec\jmath

or -\vec n = \vec \jmath; either way, the integral reduces to

\displaystyle \iint_S \vec E \cdot d\,\vec\sigma = \int_0^1 \int_0^1 (-x\,\vec\imath + z\,\vec k) \cdot (\pm\vec\jmath) \, dx\,dz = \boxed{0}

3 0
2 years ago
You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

h=v_{0}t+\frac{1}{2}gt^2

where h is the height, v_{0} is the initial velocity, in this case v_{0}=0. g is the acceleration of gravity: g=9.81m/s and t is time, thus:

h=\frac{1}{2}gt^2

clearing for time:

2h=gt^2\\\frac{2h}{g}=t^2\\\sqrt{\frac{2h}{g}} =t

we know that the egg has to fall for 44.2m, so h=44.2, and g=9.81m/s, so we the time is:

t=\sqrt{\frac{2(44.2m)}{9.8m/s^2} }=\sqrt{\frac{88.4m}{9.81m/s^2} } =\sqrt{9.011s^2}= 3.002s

Finally, if the professor has a speed of v=1.2m/s, it has to be at a distance:

d=vt

and t=3.002s:

d=(1.2m/s)(3.002s)=3.6m

so the answer is the professor has to be 3.6m far from the building when you release the egg

7 0
3 years ago
(8c7p26) During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with lar
likoan [24]

Answer: 1175 J

Explanation:

Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."

Given

Spring constant, k = 102 N/m

Extension of the hose, x = 4.8 m

from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m

Work done =

W = 1/2 k [x(i)² - x(f)²]

Since x(f) = 0, then

W = 1/2 k x(i)²

W = 1/2 * 102 * 4.8²

W = 1/2 * 102 * 23.04

W = 1/2 * 2350.08

W = 1175.04

W = 1175 J

Therefore, the hose does a work of exactly 1175 J on the balloon

7 0
3 years ago
3. How did Kepler's work influence Newton?
Katarina [22]

Johannes Kepler and his laws were a great influence on Isaac Newton. ... Newton used his laws of gravity and motion to derive Kepler's laws and show that the motion of the planets could be explained using mathematics and physics.

3 0
3 years ago
Read 2 more answers
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