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inna [77]
3 years ago
8

Solve for x x-3/4=x/10

Mathematics
1 answer:
BARSIC [14]3 years ago
3 0
Given  <span>x-3/4=x/10  find the LCD.  It is 20, as both 4 and 10 divide evenly into 20.

Then you have 20x - 15 = 2x, or 18x = 15, or x = 15/18, or x =5/6 (answer).</span>
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What is the difference between rates and proportions???
frez [133]
A rate often involves time:  e. g., 33 feet per second; also, we are finding the ratio of one type of measurement with respect to another:  distance and time.

A proportion is often the ratio of different measures of the same thing:

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6 0
3 years ago
An Olympic hurdler was part of the way through her race when she fell. She got up and completed the final 353535 meters of her 1
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3 years ago
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

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Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

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<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
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7 0
2 years ago
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7 0
2 years ago
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