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2 years ago

When your body is warmed by an electric blanket during the winter, this process is said to be

2 answers:

8 0

The correct answer would be A. endothermic because endothermic is-<span>(of a reaction or process) accompanied by or requiring the absorption of heat. Hope this helps!:) If you need any more just tag me.

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Ad libitum [116K]2 years ago

3 0

Explanation :

When your body is warmed by an electric blanket during the winter, this process is said to be an endothermic process. This is because in this process, the heat is absorbed from the blanket and it does not allow to pass out from it.

In the exothermic process, the heat is released in the surrounding.

In the isothermic process, the temperature remains the same.

Hence, the correct option is (A) "endothermic process".

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A 15.0 mW laser puts out a narrow beam 2.00 mm indiameter.

Murljashka [212]

Answer:

1341.03 V/m

Explanation:

The power output per unit area is the intensity and also the is the magnitude of the Poynting vector.

$S = \frac{P}{A}$ = cε₀ $E^{2} _{rms}$

⇒ $\frac{P}{A}$ = cε₀ $E^{2}_{rms}$

Where;

P is the power output

A is the area of the beam

c is speed of light

ε₀ is permittivity of free space 8.85 × 10⁻¹² F/m

$E_{rms}$ is the average (rms) value of electric field

Making electricfield $E_{rms}$ the subject of the equation

$E^{2}_{rms}$ = P / Acε₀

$E_{rms}$ = √(P / Acε₀)

But area A = πr²

$E_{rms}$ = √(P / πr²cε₀)

Given:

Output power, P = 15 mW = 0. 015 W

Diameter, d = 2 mm = 0.002 m

⇒ Radius, $r = \frac{d}{2} = \frac{0.002}{2} = 0.001 m$

Solving for average (rms) value of electric field;

$E_{rms} = \sqrt{\frac{0.015 W}{\pi * (0.001 m)^2 * (3 * 10^8 m/s) * (8.85 * 10^-12) C^2/Nm^2} }$

$E_{rms}$ = 1341.03 V/m

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3 years ago

Chemical energy stored in food cannot be transformed into mechanical energy true or false

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If that statement were true, then you would never have any reason to eat.
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Explanation:

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Answer:

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2 years ago

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Vsevolod [243]

Answer:

anions

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