Answer:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Explanation:
At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:
(1)
(2)
Where:
- Magnitude of the force, measured in newtons.
- Direction of the force above the horizontal surface, measured in sexagesimal degrees.
If we know that 
and 
, then the components of the force is:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Answer:
Explanation:
In the whole process , electric potential energy is converted into kinetic energy .
Kinetic energy = 3.83 MeV
= 3.83 x 1.6 x 10⁻¹⁶ J
= 6.128 x 10⁻¹⁶ J .
Let the closest distance of approach be r .
Electric potential energy = k Q q / r , Q is charge on nucleus , q is charge on alpha particle , r is closest distance .
Electric potential energy = 9 x 10⁹ x 79 x 1.6 x 10⁻¹⁹ x 2 x 1.6 x 10⁻¹⁹ / r
= 3640.32 x 10⁻²⁹ / r
So,
6.128 x 10⁻¹⁶= 3640.32 x 10⁻²⁹ / r
r = 3640.32 x 10⁻²⁹ / 6.128 x 10⁻¹⁶
= 594.05 x 10⁻¹³
= 59.405 x 10⁻¹²
= 59.405 pm .
Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE
Answer:
C. The process through which distinct layers with characteristic chemical and/or physical properties are formed
Explanation:
I know It cause i took that test last year. Just wanna help GL.
