Hi guys I suggest to make group to exchange the informations if they need add their name here
2 answers:
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Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :
J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.
W = -35.1348 Joules
Hence, this is the required solution.
Answer:
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.