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RoseWind [281]
3 years ago
11

What is the maximum rated voltage for a 100 ohm 1/4 watt resistor?

Physics
1 answer:
Debora [2.8K]3 years ago
3 0
This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400  I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
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Consider the following equilibrium at 979 K for the dissociation of molecular iodine into atoms of iodine. I2(g) equilibrium rea
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Explanation:

Initial moles of  I_2 = 0.072 mole

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The given balanced equilibrium reaction is,

                 I_2(g)\rightleftharpoons 2I(g)

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At eqm. conc.    (0.018-x) M      (2x) M  

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[I]^2}{[I_2]}

K_c=\frac{(2x)^2}{0.2-x}

we are given :  K_c=1.60\times 10^{-3}

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1.60\times 10^{-3}=\frac{(2x)^2}{(0.018-x)}

x=0.0025

So, the concentrations for the components at equilibrium are:

[I]=2\times x=2\times 0.0025=0.0050

[I_2]=0.018-x=0.018-0.0025=0.0155

Hence, concentrations of I_2 and I are 0.0050 M ad 0.0155 M respectively.

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