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sergejj [24]
3 years ago
11

What three machines or devices depend of gravity to work?

Physics
1 answer:
Anarel [89]3 years ago
4 0
Satellites scales and a grandfather clock<span />
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A 5.0 mm diameter proton beam carries a total current of 1.5mA. The current density in the proton beam, which increases with dis
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Answer:

Jedge = 0.076A/cm^2

Explanation:

If you want to know what is Jedge is convenient to use an integral. The total density current is given by:

J_T=\int_{0}^{R}J_{edge}(\frac{r}{R})dr=J_{edge}(\frac{1}{R})(\frac{R^2}{2})=\frac{J_{edge}R}{2}  (1)

But also, we have that the total current is

I_T=J_TA\\\\J_T=\frac{I_T}{A}=\frac{1.5*10^{-3}A}{\pi(5*10^{-3})^2}=19.09\frac{A}{m^2}

where we have used that 5mm=5*10^{-3}m.

By replacing (1) we obtain:

J_{edge}=\frac{2J_T}{R}=\frac{2(19.09A/m^2)}{5*10^{-3}m}=7639.4\frac{A}{m^2}=0.076\frac{A}{cm^2}

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Challenge question: An arrow is placed at 3 centimeters to the left of a converging lens. The image appears at 3 centimeters to
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The focal length of the converging lens based on the arrow placed  3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.

<h3>Focal length of the converging lens</h3>

The focal length of the converging lens is determined by applying the following converging lens formula.

1/f = 1/v + 1/u

where;

  • v is the image distance = 3 cm
  • u is the object distance = 3 cm
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1/f = 1/3 + 1/3

1/f = 2/3

f = 3/2

f = 1.5 cm

Thus, the focal length of the converging lens is 1.5 cm.

Learn more about converging lens here: brainly.com/question/22394546

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Ultraviolet light of wavelength of 350nm and intensity 1 W/m2 is directed at a potassium surface. Here energy of the photon is 1
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