A stone is thrown straight up. when it reaches it’s highest point, ____

A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a

Fudgin [204]

Answer:

Temperature will be 305 K

Explanation:

We have given The asteroid has a surface area $A=7.70m^2$

Power absorbed P = 3800 watt

Boltzmann constant $\sigma =5.67\times 10^{-8}Wm/K^4$

According to Boltzmann rule power radiated is given by

$P=\sigma AT^4$

$3800=5.67\times 10^{-8}\times 7.70\times T^4$

$T^4=87.0381\times 10^8$

$T=305K$

So temperature will be 305 K

8 0

3 years ago

5. Calculate the acceleration of a 2 kg block across a table if you push with a force of 20 N and the frictional force is 4 N.

frozen [14]

Answer:

Explanation:hey do you go to GOC too?

8 0

2 years ago

Please help, and show steps. Thank you very much!

Vikentia [17]

V = 8 * 10^2 km/h = 800km/h
S= 1,8* 10^3 km = 1800km
t = ?
v = S/t
t = S/v
t = 1800km/ 800km/h
t ≈ 2,25h (135min)

6 0

4 years ago

51. Suppose you measure the terminal voltage of a 3.200-V lithium cell having an internal resistance of 5.00Ω by placing a 1.00-

Tanya [424]

Explanation:

Given that,

Terminal voltage = 3.200 V

Internal resistance $r= 5.00\ \Omega$

(a). We need to calculate the current

Using rule of loop

$E-IR-Ir=0$

$I=\dfrac{E}{R+r}$

Where, E = emf

R = resistance

r = internal resistance

Put the value into the formula

$I=\dfrac{3.200}{1.00\times10^{3}+5.00}$

$I=3.184\times10^{-3}\ A$

(b). We need to calculate the terminal voltage

Using formula of terminal voltage

$V=E-Ir$

Where, V = terminal voltage

I = current

r = internal resistance

Put the value into the formula

$V=3.200-3.184\times10^{-3}\times5.00$

$V=3.18\ V$

(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf

$\dfrac{Terminal\ voltage}{emf}=\dfrac{3.18}{3.200 }$

$\dfrac{Terminal\ voltage}{emf}= \dfrac{159}{160}$

Hence, This is the required solution.

5 0

3 years ago

A cubical Gaussian surface surrounds two positive charges, each has a charge q 1 1 = + 3.90 × 10 − 12 3.90×10−12 C, and three ne

Masteriza [31]

Answer:

The electric flux is zero because charge is zero.

Explanation:

Given that,

Positive charge $q_{1}=3.90\times10^{-12}\ C$

Negative charge $q_{2}=-2.60\times10^{-12}\ C$

We need to calculate the total charged

Using formula of charge

$Q_{enc}=2q_{1}+3q_{2}$

Put the value into the formula

$Q_{enc}=2\times3.90\times10^{-12}+3\times(-2.60\times10^{-12})$

$Q_{enc}=0$

We need to calculate the electric flux

Using formula of electric flux

$\phi=\dfrac{Q_{enc}}{\epsilon_{0}}$

Put the value into the formula

$\phi=\dfrac{0}{8.85\times10^{-12}}$

Hence, The electric flux is zero because charge is zero.

7 0

3 years ago

A stone is thrown straight up. when it reaches it’s highest point, _____