Answer:
 
Explanation:
According to the question
net force F = 2.20×10^6 N
displacement 
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19°   ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S
 
 
 
        
             
        
        
        
B.earth rotates on its axis in 24 hours; i.e., it rotates 15° of longitude per hour.
        
             
        
        
        
Answer:
a. 12.12°
b. 412.04 N
Explanation:
Along vertical axis, the equation can be written as
 T_1 sin14 + T_2sinA = mg
 T_2sinA = mg - T_1sin12.5           ....................... (a)
Along horizontal axis, the equation can be written as
T_2×cosA = T_1×cos12.5    ......................... (b)
(a)/(b) given us
 Tan A = (mg - T_1sin12.5) / T_1 cos12.5
  = (176 - 413sin12.5) / 413×cos12.5
 A = 12.12 °
(b) T2 cosA = T1 cos12.5
 T2 = 413cos12.5/cos12.12
 = 412.04 N
 
        
                    
             
        
        
        
Hi there!
We can begin by calculating the time taken to reach its highest point (when the vertical velocity = 0).
Remember to break the velocity into its vertical and horizontal components.
Thus:
0 = vi - at
0 = 16sin(33°) - 9.8(t)
9.8t = 16sin(33°)
t = .889 sec
Find the max height by plugging this time into the equation:
Δd = vit + 1/2at²
Δd = (16sin(33°))(.889) + 1/2(-9.8)(.889)²
Solve:
Δd = 7.747 - 3.873 = 3.8744 m
 
        
                    
             
        
        
        
Answer:
the tension of the rope is 34.95 N
Explanation:
Given;
length of the rope, L = 3 m
mass of the rope, m = 0.105 kg
frequency of the wave, f = 40 Hz
wavelength of the wave, λ = 0.79 m 
Let the tension of the rope = T
The speed of the wave is given as;

Therefore, the tension of the rope is 34.95 N