<h2>Answer: The tsunami occurred on 1958 at Lituya Bay, Alaska.
</h2>
The Lituya Bay tsunami occurred on July 9th, 1958, northeast of the Gulf of Alaska. It was as a consequence of a strong earthquake of magnitude 8.3 on the Ritchter scale along the Fairweather Fault in the Alaskan Panhandle, which caused a landslide in a fjord in Lituya Bay, collapsing an entire mountain and generating a gigantic wave that rose to <u>524 meters</u>, the highest recorded so far.
It should be noted that despite its great magnitude and having uprooted all the trees and vegetation of the place, this mega-tsunami claimed only five lives because the area was not as inhabited as the large cities are.
Answer:
Explanation:
It's a good thing to claim this was speed and not velocity.
Givens
d = 40 meters
t = 5 seconds
V = ??
Formula
v = d/t
Solution
v = 40 m/5 sec
v = 8 m/s
If you really wanted to get picky, you should convert the distance to yards which is how distance is measured in football
1.09 yards = 1 meter
d = 40 * 1.09 = 43.74 yards.
t = 5 seconds
v = 43.74/5 = 8.749 yards / second.
Pacific Plate<span> and </span>Juan de Fuca<span> 6.</span>
- A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head on collision with a 14.0 kg raft moving to the right at 16.0 m/s.
- After the collision the raft moves to the left at 14.4 m/s assuming water simulates a frictionless surface.
- Mass of the canoe (m1) = 16 Kg
- Mass of the raft (m2) = 14 Kg
- Initial velocity of the canoe (u1) = 12.5 m/s
- Initial velocity of the raft (u1) = - 16 m/s [Here, the raft's velocity is negative, because the objects are moving in the opposite direction]
- Total momentum of the system = m1u1 + m2u2 = [(16 × 12.5) + (14 × -16)] Kg m/s = (200 - 224) Kg m/s = -24 Kg m/s
- Final velocity of the raft (v2) = 14.4 m/s
- Let the final velocity of the canoe be v1.
- Total momentum of the system after the impact = m1v1 + m2v2 = [(16 × v1) + (14 × 14.4)] Kg m/s = 16v1 Kg + 201.6 Kg m/s
- According to the law of conservation of momentum, Total momentum of the system before the impact = Total momentum of the system after the impact
- or, -24 Kg m/s = 16v1 Kg + 201.6 Kg m/s
- or, -24 Kg m/s - 201.6 Kg m/s = 16v1 Kg
- or, -225.6 Kg m/s = 16v1 Kg
- or, v1 = -225.6 Kg m/s ÷ 16 Kg
- or, v1 = -14.1 m/s
<u>Answer:</u>
<u>T</u><u>he final velocity of the </u><u>canoe </u><u>is </u><u>-</u><u>1</u><u>4</u><u>.</u><u>1</u><u> </u><u>m/</u><u>s </u><u>or </u><u>1</u><u>4</u><u>.</u><u>1</u><u> </u><u>m/</u><u>s </u><u>to </u><u>the </u><u>right.</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
We only need to look at Newton's 2nd law of motion:
Net force = (mass) x (acceleration)
If the net force on an object is zero, then either its mass or its acceleration must be zero. If it's called an "object", then its mass isn't zero, so its acceleration is zero.