A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house
1 answer:
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Answer:
(a). The acceleration is 3.20 m/s².
(b). The amount of work done by each force is 19.2 J.
(c). The total work done on the block is 19.2 J.
(d). The final speed of the block is 6.26 m/s.
Explanation:
Given that,
Mass of block = 3 kg
Distance = 2 m
Angle = 30°
Coefficient of kinetic friction = 0.20
(a). We need to calculate the acceleration
Using balance equation of force
Put the value into the formula
The acceleration is 3.20 m/s².
(b). We need to calculate the amount of work done by each force
Using formula of work done
Normal force is
So due to this the net force is zero then the no work done by reaction force.
By another force,
Put the value into the formula
The amount of work done by each force is 19.2 J.
(c). We need to calculate the total work done on the block
The total work done on the block is 19.2 J.
(d). We need to calculate the final speed of the block
Using equation of motion
Put the value into the formula
The final speed of the block is 6.26 m/s.
Hence, This is the required solution.
Answer:
<em>The skydiver needs 0.71 seconds to reach 7 m/s</em>
Explanation:
<u>Free Fall Motion </u>
When an object is dropped in free air (no friction) from a certain height h, it follows a free-fall motion, whose acceleration is due exclusively to gravity. The speed at a moment t when the object is dropped (from rest) is:
We need to find How long does the skydiver needs to reach 7 m/s. We solve for t
The skydiver needs 0.71 seconds to reach 7 m/s