The electromotive force on the free electrons in the wire is given by
E=vBl
where v is the velocity, B is the field component perpendicular to the wire and l is the length of the wire. So we get
E=15.6*40E-6*2.5m=1.56mV
Now the force that causes this to happen is given by F=q(v X B) where q is the charge on the electron which is negative. the cross product of the velocity and magnetic field points in a direction that is westward. Since the electrons are negative they are pushed to the east, leaving the west end of the wire with a positive charge .
Given that a shape is a parallelogram, the answer that is sufficient to state that it is also a rectangle is that C. The opposite sides are parallel.
A is not enough - this would mean it is a square, not a rectangle.
<span>3640 m/s
The de Broglie wavelength of a particle is expressed by the equation:
λ = h/p
where
λ = wavelength
h = Planck constant
p = momentum
so let's solve for momentum and the substitute the known values and calculate:
λ = h/p
λp = h
p = h/λ
p = 6.62607004x10^-34 Js/2x10^-7 m
p = 6.62607004x10^-34 kg*m^2/s^2 * s/2x10^-7 m
p =3.31303502x10^-27 kg*m/s
Now momentum is defined as mass times velocity. And the mass of an electron is 9.10938356Ă—10^-31 kg. So
p = mv
p/m = v
3.31303502x10^-27 kg*m/s / 9.10938356Ă—10^-31 kg = v
3.63694754774384x10^3 m/s = v
Rounding to 3 significant figures gives 3.64x10^3 m/s or 3640 m/s. That velocity is low enough that we don't need to worry about relativistic effects.</span>
The correct answer is A:) hope it helps :0
Answer:
v=343m/s
Explanation:
We have to take into account the expressions
if we assume that 256Hz is the fundamental frequency we have
and for wavelength
hope this helps!!