A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house
1 answer:
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Answer: The correct option is (c.).
Explanation:
Mass of the cart A= 1.5 kg
Velocity of Cart A = 1.4 m/s towards right
Mass of the cart B = 1.0 kg
Velocity of Cart B = 1.4 m/s towards left
Momentum (P)= Mass × Velocity
(Negative sign means velocity of the cart is in opposite direction of that of the cart A)
Total Momentum =
Hence, the correct option is (c.).
Answer:
force = 1 × N
Explanation:
given data
automobile mass = 1200 kg
insect mass = 0.0001 kg
insect accelerated = 100 m/s²
to find out
magnitude of the force the insect exerts on the car
solution
we get here force the insect exerts that is express as
force = mass × acceleration ............1
put here value we get
force = 0.0001 × 100 m/s²
force = 1 × N
Answer:
0.767
Explanation:
The work done on the truck by the frictional drag force is given by
where
F is the magnitude of the frictional force
d = 38.0 m is the maximum displacement allowed for the truck
The negative sign is due to the fact that the force of friction is opposite to the motion of the truck
The force of friction can also be written as:
where
is the coefficient of kinetic friction between the truck and the lane
m is the mass of the truck
g is the acceleration of gravity
So we can rewrite the work done as
(1)
According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:
(2)
where
v = 0 is the final velocity of the truck
u = 23.9 m/s is the initial velocity of the truck
By combining (1) and (2) we get
And solving for , we find the minimum coefficient of kinetic friction able to stop the truck in a distance d: