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3 years ago

Compare and contrast CLF and LED bulbs.

Physics

1 answer:

Arte-miy333 [17]3 years ago

4 0

Explanation:

Comparison Chart

Basis For Comparison CFL Bulb LED Bulb

Definition The CFL is defined as the lamp which uses the low pressure mercury vapour gas for producing the visible light It is a PN junction diode which produces light when current passes through it in the forward direction.

Stand For Compact Fluorescent Lamp Light Emitting Diode

Working principle The electrons of mercury when excited emits ultraviolet light. This ultraviolet light when strikes with the fluorescent coating glass converts it into the visible light. The semiconductor material which emits light with the passage of current.

Power Consumption More Less

Mercury Contain Not contain

Destruction Difficult Easy

Efficient Less More

Ballast Requires Not requires

Lifespan 10,000 hours 50,000 hours and more.

Turn on Intensity Delay Quick

Expensive Less More

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The pressure of a fluid at a specific depth depends only on the type of fluid?

timurjin [86]

I think yes the density

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3 years ago

An object is place 30.5 cm from a convex lens that has a focal length of 8.0cm.where is the image ?

77julia77 [94]

Answer:

Image is between F and 2F. And the exact location is:

q = 10.84 cm

Explanation:

The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:

1. Image is real.

2. Image is inverted

3. Image is diminished

<u>4. Image is located between F and 2F</u>

For exact location we use the thin lens formula:

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where,

f = focal length = 8 cm

p = object distance = 30.5 cm

q = image distance = ?

Therefore,

$\frac{1}{8\ cm} = \frac{1}{30.5\ cm} + \frac{1}{q} \\\frac{1}{8\ cm} - \frac{1}{30.5\ cm} = \frac{1}{q}$

7 0

3 years ago

What would be the atomic number of an atom that is composed of 15 protons and 18 neutron?

Anuta_ua [19.1K]

Answer:

Explanation:

atomic no. = no. of protons

6 0

3 years ago

Se lanza una bala con una velocidad inicial de 200 m/s y con un ángulo de inclinación de 30º respecto a la horizontal. Si se con

puteri [66]

Answer:

El alcance de la bala es 3464,1 m.

Explanation:

El alcance de la bala se puede calcular como sigue:

$y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}$

En donde:

y: es la altura final = 0

$y_{0}$ : es la altura inicial = 0

x: es el alcance

θ: es el angulo respecto a la horizontal = 30°

$v_{0}$ : es la velocidad inicial = 200 m/s

g: es la gravedad = 10 m/s²

Entonces, tenemos:

$y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}$

$x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(30)*(200 m/s*cos(30))^{2}}{10 m/s^{2}} = 3464,1 m$

Por lo tanto, el alcance de la bala es 3464,1 m.

Espero que se te sea de utilidad!

8 0

4 years ago

1) What is the weight of a 356kg object?

stiks02 [169]

1) 3489 N

2) The microbumps over the surfaces

3) See explanation

Explanation:

The gravitational force acting on an object (also known as weight of the object) is the attractive force with which the Earth pulls the object towards the ground.

It can be calculated using the formula:

$W=mg$

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m = 356 kg is the mass of the object

$g=9.8 m/s^2$ is the acceleration due to gravity

Therefore, the weight of the object is:

$W=(356)(9.8)=3489 N$

The force of friction is a force that acts whenever there is an object sliding over a surface. It is a resistive force, therefore its direction is always opposite to the direction of motion of the object.

On a microscopic scale, the reason of this force of friction is the presence of "microbumps" over the surface of the sliding object (and over the surface of the floor). Because of the roughness of the two surfaces, the molecules of the two surfaces "interact" and cause a resistive force that opposes the relative motion of the object over the surface.

Macroscopically, for an object over a flat surface, the magnitude of the force of friction is

$F_f=\mu mg$

where

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

There are two types of force of friction:

- Force of static friction: this occurs when the object is still at rest. We experience this force when we try to put in motion an object on the ground, by applying a push: we notice that if the force we apply is not strong enough, the object will remain at rest. This is because there is a static force of friction acting on the object, that equals the force of push that we are applying, but in the opposite direction. The magnitude of the force of friction can vary up to a maximum value, given by

$F_{max}=\mu_s mg$

where

$\mu_s$ is the coefficient of static friction

m is the mass of the object

g is the acceleration due to gravity

- Force of kinetic friction: this is the force of friction that occurs when the object is already in motion. The kinetic force of friction opposes the motion of the object, and its magnitude is

$F_k = \mu_k mg$

where

$\mu_k$ is the coefficient of kinetic friction

Generally, for most surfaces, $\mu_k < \mu_s$ , therefore the force of kinetic friction is generally less than the force of static friction.

4 0

3 years ago