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Ratling [72]
2 years ago
12

Compare and contrast CLF and LED bulbs.

Physics
1 answer:
Arte-miy333 [17]2 years ago
4 0

Explanation:

Comparison Chart

Basis For Comparison CFL Bulb LED Bulb

Definition The CFL is defined as the lamp which uses the low pressure mercury vapour gas for producing the visible light It is a PN junction diode which produces light when current passes through it in the forward direction.

Stand For Compact Fluorescent Lamp Light Emitting Diode

Working principle The electrons of mercury when excited emits ultraviolet light. This ultraviolet light when strikes with the fluorescent coating glass converts it into the visible light. The semiconductor material which emits light with the passage of current.

Power Consumption More Less

Mercury Contain Not contain

Destruction Difficult Easy

Efficient Less More

Ballast Requires Not requires

Lifespan 10,000 hours 50,000 hours and more.

Turn on Intensity Delay Quick

Expensive Less More

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To find the specific heat capacity of a solid of mass 600 g whose temperature was 40oC, it was placed in a calorimeter that cont
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3 years ago
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Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ
Oksi-84 [34.3K]

Answer:

The number is  Z = 216 \ fringes

Explanation:

From the question we are told that

      The wavelength is  \lambda  =  520 \ nm =  520 *10^{-9} \ m

       The length of the glass plates is y  = 21.1cm = 0.211 \ m

      The distance between the plates (radius of wire ) =  d =  0.028 mm  =  2.8 *10^{-5} \  m

   Generally the condition for constructive  interference in a film is mathematically represented as

            2 *  t  = [m +  \frac{1}{2}  ]\lambda

Where  t is the thickness of the separation between the glass i.e  

    t  = 0 at the edge where the glasses are touching each other and  

     t =  2d at the edge where the glasses are separated by the wire  

   m is the order of the fringe it starts from  0, 1 , 2 ...

So  

       2 *  2 * d   = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>   2 *  2 *   (2.8 *10^{-5}) = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>    

       m = 215

given that we start counting m from zero

   it means that the number of  bright fringes that would appear is

         Z =  m + 1

=>    Z =  215 +1

=>     Z = 216 \ fringes

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