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Marianna [84]
4 years ago
10

You are operating a pwc. you are heading straight toward a dock. you turn the engine off and then turn the steering control hard

right. which way will the pwc go?
Physics
1 answer:
White raven [17]4 years ago
6 0
In this case, the PWC will head for the dock. This is because, power needs to be applied in order to maintain steering control. If the throttle is left to idle or if the engine is turn off during operation, all steering control will be lost. In each of this situation, the PWC will continue in the was headed before the engine was turned off or before the throttle was left to idle.  
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A car’s headlights dissipate 40 W on low beam and 50 W on high beam. Is there more or less resistance in the high-beam filament?
love history [14]

Answer:

The high-beam filament has more resistance than low beam filament.

Explanation:

To determine if the 50 W dissipated by a car’s headlights on high beam, has more or less resistance, formula for power dissipated in the filament is used.

Power = IV

Voltage =IR

∴ Power = I*IR = I²R

where;

I is the current

V is the voltage

R is the resistance

From the equation above, Power dissipated is directly proportional to Resistance.

Hence, the high-beam filament has more resistance than low beam filament.

3 0
3 years ago
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
Given that o.2i+bj+o.4k is a unit vector,what is the value of b?
pishuonlain [190]

Answer:

b = 0.89

Explanation:

The given vector is, A=0.2i+bj+0.4k

A is a unit vector

We need to find the value of b.

For a unit vector, |A| = 1

So,

0.2^2+b^2+0.4^2=1\\\\0.04+b^2+0.16=1\\\\0.2+b^2=1\\\\b^2=1-0.2\\\\b=0.89

So, th value of b is 0.89.

6 0
3 years ago
What must a system owner do, once the threshold leak rate has been exceeded on any low-pressure system using an ozone-depleting
soldier1979 [14.2K]

Answer:

A procedure according to the norms.

Explanation:

If possible, proceed to fix the leak in no more than 30 days from the moment it was discovered.

Otherwise, during the first 30 days develop a planification to backfit the leak or, if needed, retire the appliance. This should be executed within one year.

7 0
3 years ago
Three identical resistors are connected in parallel to a battery. If the current of 12. A flows from the battery, how much curre
Doss [256]

Answer:

4 A

Explanation:

We are given that

R_1=R_2=R_3=4\Omega

I=12 A

We have to find the current flowing through each resistor.

We know that in parallel combination current flowing through different resistors are different and potential difference across each resistor is same.

Formula :

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

Using the formula

\frac{1}{R}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{3}{4}

R=\frac{4}{3}\Omega

V=IR

Substitute the values

V=12\times \frac{4}{3}=16 V

I_1=\frac{V}{R_1}=\frac{16}{4}=4 A

I_1=I_2=I_3=4 A

Hence, current flows through any one of the resistors is 4 A.

7 0
3 years ago
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