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ICE Princess25 [194]
3 years ago
15

Because of the mud in the muddy water eventually settles out the muddy water is a ____________.

Chemistry
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

solution

Explanation:

i just took the test

sp2606 [1]3 years ago
6 0

it should be B. solution; a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).

witch basically means it sorts it self out when left a lone, like soap and water when not touched or the oil in the dressings you get at the store. hope this helped :D


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PLEASE ANSWER
zhuklara [117]
D) light is reflecting in the direction indicated by T.
6 0
3 years ago
Read 2 more answers
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
3 years ago
Still using the reaction from the video, what is the limiting reagent when 2 moles of Al are reacted
kondaur [170]

The limiting reagent will be Al

<h3>What are limiting reagents?</h3>

They are reagents that limit the quantity of products that are formed in reactions.

From the equation of the reaction:

4Al + 3O_2 --- > 2Al_2O_3

The mole ratio of Al to O2 is 4:3.

With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.

With 2 moles of O2, the amount of Al required should be:

                          2 x 4/3 = 2.67 moles.

With 2 moles of Al, the amount of O2 required should be:

                    2 x 3/4 = 1.5 moles

Thus, O2 is in excess by 0.5 moles.

More on limiting reagents can be found here: brainly.com/question/11848702

#SPJ1

8 0
2 years ago
Scientist have genetically altered a common virus so that it can Destroy the most lethal type of brain tumor without harming the
sergey [27]

Answer:

The correct answer is - discovering or diagnosing the disease.

Explanation:

According to the question, this technology includes genetically modifying a common virus in order to destroy or kill the deadly brain tumor without affecting normal cells around the tumor, this technique is genetic engineering.

This technique can help in treating or curing the disease by killing the tumor cells and make them non-lethal. It can also prevent the tumor cells to grow and make them controlled. There is nothing mention related to diagnosing the disease in the question and it is not possible to find this tumor with help of such a technique.

3 0
2 years ago
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